Borderou de evaluare (job #965640)

Utilizator Andrei_PavelAndrei Pave Andrei_Pavel Data 24 iunie 2013 12:57:44
Problema Order 2 Status done
Runda Arhiva de probleme Compilator cpp | Vezi sursa
Scor 0

Raport evaluator

Eroare de compilare: user.cpp:6:32: error: too many decimal points in number A :array[1..1000] of longint; ^ user.cpp:35:15: warning: character constant too long for its type [enabled by default] assign(fil,'order2.in'); ^ user.cpp:41:15: warning: character constant too long for its type [enabled by default] assign(fil,'order2.out'); ^ user.cpp:3:1: error: ‘var’ does not name a type var ^ user.cpp:5:4: error: ‘N’ does not name a type N,i,j,k :longint; ^ user.cpp:6:25: error: found ‘:’ in nested-name-specifier, expected ‘::’ A :array[1..1000] of longint; ^ user.cpp:6:4: error: ‘A’ does not name a type A :array[1..1000] of longint; ^ user.cpp:7:25: error: found ‘:’ in nested-name-specifier, expected ‘::’ b :pointer; ^ user.cpp:7:4: error: ‘b’ does not name a type b :pointer; ^ user.cpp:9:1: error: ‘Procedure’ does not name a type Procedure Swap(var s1,s2:longint); ^ user.cpp:10:1: error: ‘var’ does not name a type var t:longint; ^ user.cpp:11:1: error: ‘begin’ does not name a type begin ^ user.cpp:12:10: error: ‘s1’ does not name a type t:=s1; s1:=s2; s2:=t ^ user.cpp:12:18: error: ‘s2’ does not name a type t:=s1; s1:=s2; s2:=t ^ user.cpp:15:1: error: ‘Procedure’ does not name a type Procedure Flip(k:longint); ^ user.cpp:16:1: error: ‘var’ does not name a type var i:longint; ^ user.cpp:17:1: error: ‘begin’ does not name a type begin

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