Borderou de evaluare (job #965640)
Utilizator | Data | 24 iunie 2013 12:57:44 | |
---|---|---|---|
Problema | Order 2 | Status | done |
Runda | Arhiva de probleme | Compilator | cpp | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
user.cpp:6:32: error: too many decimal points in number
A :array[1..1000] of longint;
^
user.cpp:35:15: warning: character constant too long for its type [enabled by default]
assign(fil,'order2.in');
^
user.cpp:41:15: warning: character constant too long for its type [enabled by default]
assign(fil,'order2.out');
^
user.cpp:3:1: error: ‘var’ does not name a type
var
^
user.cpp:5:4: error: ‘N’ does not name a type
N,i,j,k :longint;
^
user.cpp:6:25: error: found ‘:’ in nested-name-specifier, expected ‘::’
A :array[1..1000] of longint;
^
user.cpp:6:4: error: ‘A’ does not name a type
A :array[1..1000] of longint;
^
user.cpp:7:25: error: found ‘:’ in nested-name-specifier, expected ‘::’
b :pointer;
^
user.cpp:7:4: error: ‘b’ does not name a type
b :pointer;
^
user.cpp:9:1: error: ‘Procedure’ does not name a type
Procedure Swap(var s1,s2:longint);
^
user.cpp:10:1: error: ‘var’ does not name a type
var t:longint;
^
user.cpp:11:1: error: ‘begin’ does not name a type
begin
^
user.cpp:12:10: error: ‘s1’ does not name a type
t:=s1; s1:=s2; s2:=t
^
user.cpp:12:18: error: ‘s2’ does not name a type
t:=s1; s1:=s2; s2:=t
^
user.cpp:15:1: error: ‘Procedure’ does not name a type
Procedure Flip(k:longint);
^
user.cpp:16:1: error: ‘var’ does not name a type
var i:longint;
^
user.cpp:17:1: error: ‘begin’ does not name a type
begin
Ceva nu functioneaza?
- Citeste despre borderoul de evaluare.
- Daca tot nu e bine, contacteaza-ne pe forum !