Cod sursa(job #306434)

Utilizator Mishu91Andrei Misarca Mishu91 Data 20 aprilie 2009 19:48:32
Problema Matrice 2 Scor Ascuns
Compilator cpp Status done
Runda Marime 1.9 kb
#include <fstream>
#include <algorithm>

using namespace std;

#define MAXN 310
#define MAXX 90010
#define MAXQ 20010
#define MAXL 4

const int dirx[MAXL] = {-1, 0, 1, 0};
const int diry[MAXL] = {0, 1, 0, -1};

int N, Q, L;
char B[MAXN][MAXN];
int W[MAXN][MAXN];
int X[MAXX], Y[MAXX], C[MAXX], P[MAXX];
int G[MAXX];
int Sol[MAXQ];
int Query[MAXQ], P2[MAXQ];
int X1[MAXQ], Y1[MAXQ], X2[MAXQ], Y2[MAXQ];

inline int cmp(int x, int y)
{
	return C[x] > C[y];
}

inline int cmp2(int x, int y)
{
	return Query[x] > Query[y];
}

inline int find_dad(int x)
{
	if (x != G[x]) G[x] = find_dad(G[x]);
	return G[x];
}

int main()
{
	ifstream fin("matrice2.in");
	ofstream fout("matrice2.out");

	int i, j, k, p, step, cx, cy;

	fin >> N >> Q;

	for (i = 1; i <= N; i++)
		for (j = 1; j <= N; j++)
		{
			L++;
			W[i][j] = L;
			X[L] = i, Y[L] = j;
			fin >> C[L];
			P[L] = L;
		}

	for (i = 1; i <= Q; i++) fin >> X1[i] >> Y1[i] >> X2[i] >> Y2[i];

	sort(P+1, P+L+1, cmp);

	for (step = 1; step < C[P[1]]; step <<= 1);

	for (; step; step >>= 1)
	{
		for (i = 1; i <= Q; i++) 
		{
			Query[i] = Sol[i] + step;
			P2[i] = i;
		}

		sort(P2+1, P2+Q+1, cmp2);
		
		for (i = 1; i <= L; i++) G[i] = i;

		for (i = 1; i <= N; i++)
			for (j = 1; j <= N; j++) B[i][j] = 0;

		for (i = 1, j = 1; i <= L; )
		{
			for (k = j; j <= Q && Query[P2[j]] > C[P[i]]; j++)
				if (find_dad( W[X1[P2[j]]][Y1[P2[j]]] ) == find_dad( W[X2[P2[j]]][Y2[P2[j]]] )) Sol[P2[j]] += step;

			for (k = i; i <= L && C[P[i]] == C[P[k]]; i++)
			{
				B[X[P[i]]][Y[P[i]]] = 1;

				for (p = 0; p < MAXL; p++)
				{
					cx = X[P[i]] + dirx[p];
					cy = Y[P[i]] + diry[p];

					if (cx > 0 && cy > 0 && cx <= N && cy <= N && B[cx][cy])
						G[G[ find_dad(W[cx][cy]) ]] = G[P[i]];
				}
			}
		}

		for (; j <= Q; j++) 
			if (find_dad( W[X1[P2[j]]][Y1[P2[j]]] ) == find_dad( W[X2[P2[j]]][Y2[P2[j]]] )) Sol[P2[j]] += step;
	}

	for (i = 1; i <= Q; i++) fout << Sol[i] << endl;

	return 0;
}