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#include <bits/stdc++.h>
#include <fstream>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
struct custom_hash {static uint64_t splitmix64(uint64_t x) {x += 0x9e3779b97f4a7c15;x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;x = (x ^ (x >> 27)) * 0x94d049bb133111eb;return x ^ (x >> 31);}size_t operator()(uint64_t x) const {static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();return splitmix64(x + FIXED_RANDOM);}};
string __fname = "scmax"; ifstream in (__fname + ".in"); ofstream out (__fname + ".out");
#define cin in
#define cout out
#define int64 long long
#define uint64 unsigned long long
#define x first
#define y second
#define pb push_back
#define pii pair <int, int>
#define pii64 pair <int64, int64>
#define db(x) cout << "> " << #x << ": " << (x) << "\n"
#define qr queries()
#define yn(x) if (x) {ctn("Yes");}else {ctn("No");}
void solve(int);
void queries(){int n;cin >> n;for (int i = 1; i <= n; i++) solve(i);}
template<class T>T ceildiv(T a, T b) {return a / b + !!(a % b);}
template<class T>T gcd (T a, T b){return (b ? gcd(b, a % b): a);}
template<class T>T lcm (T a, T b){return a * b / gcd(a, b);}
// // // // // // // // // // // // // // // // // // // // // //
/* TEMPLATE - VANILLA */
// // // // // // // // // // // // // // // // // // // // // //
const int ddx[] = {-1, -1, 0, 1, 1, 1, 0, -1};
const int ddy[] = {0, 1, 1, 1, 0, -1, -1, -1};
const int dx[] = {-1, 0, 1, 0};
const int dy[] = {0, 1, 0, -1};
const double pi = 3.14159265359;
const double eps = 1e-6;
const int64 hash_inv = 940594066;
const int64 hash_p = 101;
const int64 mod = 1e9 + 7;
const int maxn = 2e5 + 2;
int dp[maxn]; // dp[i] -> elementul minim in care se termina o subsecventa cresctoare de lungime i
int idx [maxn]; // idx[i] -> index of the last element in dp[i]
int p[maxn]; // parent[i] -> the index of the element before the last one in dp[i]
int a[maxn];
void solve(int id){
return;
}
int main(){
// ios_base::sync_with_stdio(0); cin.tie(0); cout << fixed; cout << setprecision(10);
int n;
cin >> n;
for (int i = 0; i < n; i++){
dp[i] = 2e9 + 3;
cin >> a[i];
}
for (int i = 0; i < n; i++){
int j = upper_bound(dp, dp + n, a[i]) - dp;
if (j == 0 || a[i] > dp[j-1]) {
dp[j] = a[i];
idx[j] = i;
if (j != 0) p[i] = idx[j-1];
// cout << j << " " << dp[j] << " " << idx[j] << " " << p[j] << "\n";
}
}
int k;
for (k = 0; k < n && dp[k] != 2e9 + 3; k++){}
cout << k << "\n";
int now = idx[k - 1];
while (1) {
cout << a[now] << " ";
if (now == 0) break;
if (a[p[now]] >= a[now]) break;
now = p[now];
}
return 0;
}