Cod sursa(job #1802795)

Utilizator ajeccAjechiloae Eugen ajecc Data 10 noiembrie 2016 17:31:49
Problema Deque Scor 25
Compilator cpp Status done
Runda Arhiva educationala Marime 1.99 kb
#include <bits/stdc++.h>
#define for0(i, n) for(int i = 0; i < n; i++)
#define for1(i, n) for(int i = 1; i <= n; i++)
#define pb push_back
#define mp make_pair
#define all(v) v.begin(), v.end()
#define V vector<int>
#define VP vector<pair<int, int> >
#define clr(A, x) memset(A, x, sizeof(A))
#define cpy(A, B) memcpy(A, B, sizeof(B))
#define g(s) getline(cin, s) ///ai grija la fin/cin ///
#define FASTIO ios_base::sync_with_stdio(0)
const long long INFLL = (1LL<<62);
const int INFINT = 2000000000;
typedef long long ll;
typedef unsigned long long ull;
using namespace std;
/*template <typename T>
string to_string(const T& n){
    ostringstream os;
    os << n;
    return os.str();
}
*/
/*void invers_modular(int a, int b, int &d, int &x, int &y)
{
    if(!b)
    {
        d=a;
        x=1;
        y=0;
        return ;
    }
    int x0, y0;
    invers_modular(b, a%b, d, x0, y0);
    x=y0;
    y=x0-a/b*y0;
}*/ // daca x<0 se aduna cu mod pana e mai mare, x fiind rezultatul

/*ull putere(ull baza, ull exponent, ull MOD)
{
    if(exponent == 0) return 1;
    if(exponent % 2 == 0) return putere((baza * baza) % MOD, exponent / 2, MOD) % MOD;
    return ((baza % MOD) * (putere(baza, exponent - 1, MOD) % MOD) % MOD);
}*/
ifstream fin("deque.in"); /// modifica cu numele corespunzator
ofstream fout("deque.out"); /// modifica cu numele corespunzator

int n, k, sol;
deque<pair<int, int> > v;

void add(int val, int poz)
{
    while(!v.empty() && val <= v.back().first)
        v.pop_back();
    v.push_back({val, poz});

}

int main()
{
    fin >> n >> k;
    for1(i, k - 1)
    {
        int a;
        fin >> a;
        add(a, i);
    }
    for(int i = k; i <= n; i++)
    {
        int a;
        fin >> a;
        while(!v.empty() && v.front().second <= i - k)
            v.pop_front();
        add(a, i);
      //  cout <<"->" << v.front().first <<'\n';
        sol += v.front().first;
    }
    fout << sol;

    return 0;
}