Borderou de evaluare (job #1453267)
Utilizator | Data | 23 iunie 2015 10:05:39 | |
---|---|---|---|
Problema | Transport | Status | done |
Runda | Arhiva de probleme | Compilator | cpp | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
user.cpp:9:1: error: expected ‘,’ or ‘;’ before ‘int’
int N,t[100],s,K;
^
user.cpp: In function ‘int div(int, int)’:
user.cpp:11:25: error: new declaration ‘int div(int, int)’
int div(int low,int high){
^
In file included from /usr/include/c++/4.8/cstdlib:72:0,
from /usr/include/c++/4.8/ext/string_conversions.h:41,
from /usr/include/c++/4.8/bits/basic_string.h:2815,
from /usr/include/c++/4.8/string:52,
from /usr/include/c++/4.8/bits/locale_classes.h:40,
from /usr/include/c++/4.8/bits/ios_base.h:41,
from /usr/include/c++/4.8/ios:42,
from /usr/include/c++/4.8/ostream:38,
from /usr/include/c++/4.8/iostream:39,
from user.cpp:1:
/usr/include/stdlib.h:785:14: error: ambiguates old declaration ‘div_t div(int, int)’
extern div_t div (int __numer, int __denom)
^
user.cpp:19:19: error: ‘N’ was not declared in this scope
for(int i=0;i<N;i++){
^
user.cpp:20:12: error: ‘t’ was not declared in this scope
q+=t[i];
^
user.cpp:26:11: error: ‘K’ was not declared in this scope
if(nr>K)
^
user.cpp:27:30: error: cannot convert ‘div_t’ to ‘int’ in return
return div(mid+1,high);
^
user.cpp:29:29: error: cannot convert ‘div_t’ to ‘int’ in return
return div(low,mid-1);
^
user.cpp: In function ‘int main()’:
user.cpp:35:8: error: ‘N’ was not declared in this scope
f>>N>>K;
^
user.cpp:35:11: error: ‘K’ was not declared in this scope
f>>N>>K;
^
user.cpp:36:5: error: ‘s’ was not declared in this scope
s=0;
^
user.cpp:38:12: error: ‘t’ was not declared in this scope
f>>t[i];
^
user.cpp: In function ‘int div(int, int)’:
user.cpp:31:1: warning: control reaches end of non-void function [-Wreturn-type]
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