Cod sursa(job #1250282)

Utilizator geniucosOncescu Costin geniucos Data 27 octombrie 2014 23:01:17
Problema Minesweeper Scor 100
Compilator cpp Status done
Runda Arhiva de probleme Marime 1.25 kb
#include<cstdio>

using namespace std;

int nr, n, m, X, cod[30][30];
double eps, A[500][500];

double Get (int p)
{
    return A[p][nr+1] / A[p][p];
}

void afis ()
{
    for (int i=19; i<=19; i++, printf("\n"))
        for (int j=1; j<=nr+1; j++)
            printf ("%.5lf ", A[i][j]);
}

int main()
{
freopen ("minesweeper.in", "r", stdin);
freopen ("minesweeper.out", "w", stdout);
scanf ("%d %d", &n, &m);
X = n * m;
for (int i=0; i <= X; i++)
    for (int j=0; i+j <=X; j++)
        cod[i][j] = ++nr;

for (int i=0; i<=X; i++)
    for (int j=0; i+j <=X; j++)
    {
        if (i==0 && j==0)
        {
            A[cod[i][j]][cod[i][j]] = 1.0;
            continue;
        }
        A[cod[i][j]][cod[i][j]] = 1.0;
        if (i) A[cod[i][j]][cod[i-1][j+1]] = (double) -i/X;
        if (j) A[cod[i][j]][cod[i][j-1]] = (double) -j/X;
        A[cod[i][j]][cod[i+1][j]] = (double) -(X-i-j)/X;
        A[cod[i][j]][nr+1] = 1.0;
    }

for (int i=1; i<=nr; i++)
    for (int j=i+1; j<=nr; j++)
    {
        double rap = A[j][i] / A[i][i];
        for (int k=1; k<=nr+1; k++)
            A[j][k] = (double) A[j][k] - A[i][k] * rap;
    }
printf ("%.6lf\n", (double)A[cod[X][0]][nr+1] / A[cod[X][0]][cod[X][0]]);

return 0;
}