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#include <fstream>
#include <deque>
using namespace std;
ifstream f("deque.in");
ofstream g("deque.out");
int N, K, x, a[5000005];
long long sol;
deque < int > Q;
int main()
{
f>>N>>K;
for (int i=1; i<=N; ++i)
{
f>>a[i];
while (Q.size() && a[Q.back()]>=a[i]) Q.pop_back();
Q.push_back(i);
if (Q.front()==i-K) Q.pop_front();
if (i>=K) sol+=1LL*a[Q.front()];
}
g<<sol<<'\n';
return 0;
}