Exista 5 posibilitati de a concedia angajatii (in ordine):
1) Angajatul **$1$** cu probabilitatea <tex> \(\frac{1}{3} \cdot val_1 \) </tex>;

2) Angajatii **$2$** , **$1$** cu probabilitatea <tex> \(\frac{1}{3} \cdot \frac{1}{2} \cdot (val_2 + val_3)\) </tex>;

2) Angajatii **$2$** , **$1$** cu probabilitatea <tex> \(\frac{1}{3} \cdot \frac{1}{2} \cdot (val_2 + val_1)\) </tex>;

3) Angajatii **$3$** , **$1$** cu probabilitatea <tex> \(\frac{1}{3} \cdot \frac{1}{2} \cdot (val_3 + val_1)\) </tex>;
4) Angajatii **$2$** , **$3$** , **$1$** cu probabilitatea <tex> \(\frac{1}{3} \cdot \frac{1}{2} \cdot 1 \cdot (val_2 + val_3 + val_1)\) </tex>;
5) Angajatii **$3$** , **$2$** , **$1$** cu probabilitatea <tex> \(\frac{1}{3} \cdot \frac{1}{2} \cdot 1 \cdot (val_3 + val_2 + val_1)\) </tex>;
Pentru valorile asociate initial: <tex> \(\frac{1}{3} + \frac{2}{6} + \frac{2}{6} + \frac{3}{6} + \frac{3}{6} = 2\) </tex>;

Dupa primul update: <tex> \[2 + \frac{1}{6} + \frac{1}{6} + \frac{2}{6} + \frac{2}{6} = 1\] </tex>;

Dupa primul update: <tex> \[2 + \frac{2}{6} + \frac{2}{6} + \frac{4}{6} + \frac{4}{6} = 3\] </tex>;

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