Exista 5 posibilitati de a concedia angajatii (in ordine):

1) Angajatul **$1$** cu probabilitatea <tex> \( \frac{1}{2} \) frac_{1}{3} * val [1]; </tex>
2) Angajatii **$2$** , **$1$** cu probabilitatea 1/3 * 1/2 * (val [2] + val [1]);
3) Angajatii **$3$** , **$1$** cu probabilitatea 1/3 * 1/2 * (val [3] + val [1]);
4) Angajatii **$2$** , **$3$** , **$1$** cu probabilitatea 1/3 * 1/2 * 1 * (val [2] + val [3] + val [1]);
5) Angajatii **$3$** , **$2$** , **$1$** cu probabilitatea 1/3 * 1/2 * 1 * (val [3] + val [2] + val [1]);

1) Angajatul **$1$** cu probabilitatea <tex> \(\frac{1}{3} \cdot val_1 \) </tex>;
2) Angajatii **$2$** , **$1$** cu probabilitatea <tex> \(\frac{1}{3} \cdot \frac{1}{2} \cdot (val_2 + val_3)\) </tex>;
3) Angajatii **$3$** , **$1$** cu probabilitatea <tex> \(\frac{1}{3} \cdot \frac{1}{2} \cdot (val_3 + val_1)\) </tex>;
4) Angajatii **$2$** , **$3$** , **$1$** cu probabilitatea <tex> \(\frac{1}{3} \cdot \frac{1}{2} \cdot 1 \cdot (val_2 + val_3 + val_1)\) </tex>;
5) Angajatii **$3$** , **$2$** , **$1$** cu probabilitatea <tex> \(\frac{1}{3} \cdot \frac{1}{2} \cdot 1 \cdot (val_3 + val_2 + val_1)\) </tex>;

Pentru valorile asociate initial: 1/3 + 2/6 + 2/6 + 3/6 + 3/6 = 2
Dupa primul update: 0 + 1/6 + 1/6 + 2/6 + 2/6 = 1

Pentru valorile asociate initial: <tex> \(\frac{1}{3} + \frac{2}{6} + \frac{2}{6} + \frac{3}{6} + \frac{3}{6} = 2\) </tex>;
Dupa primul update: <tex> \[0 + \frac{1}{6} + \frac{1}{6} + \frac{2}{6} + \frac{2}{6} = 1\] </tex>;

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