#include <iostream>
#include <fstream>

using namespace std;

int N, L, C;
int v[10000];

int main()
{
    ifstream f("lacate.in");
    ofstream g("lacate.out");

    f >> N;

    L = N * ( N - 1 ) / 2;
    C = N - 1;

    g << L << " " << C << "\n";

    for ( int i = 1; i <= L; i++ )
            v[i] = i;

    for ( int i = 1; i <= L; ++i )
            v[i + L] = i;

    for ( int i = 1; i <= N; ++i )
    {
        int sum = 0;

        for ( int j = i; j < i + C; ++j )
                g << v[j] << " ";

        g << "\n";
    }

    f.close();
    g.close();

    return 0;
}