Eroare de compilare: user.cpp:15:44: warning: character constant too long for its type [enabled by default] Inainte de a o explica, sa facem notatia 'element k' = element care da ^ user.cpp:37:10: warning: character constant too long for its type [enabled by default] const ni='secv.in'; ^ user.cpp:38:10: warning: character constant too long for its type [enabled by default] no='secv.out'; ^ user.cpp:2:1: error: expected unqualified-id before ‘{’ token { Dumitru Bogdan } ^ user.cpp:4:1: error: expected unqualified-id before ‘{’ token { ^ user.cpp:35:1: error: ‘program’ does not name a type program secventa; ^ user.cpp:37:7: error: ‘ni’ does not name a type const ni='secv.in'; ^ user.cpp:38:7: error: ‘no’ does not name a type no='secv.out'; ^ user.cpp:40:1: error: ‘var’ does not name a type var f:text; ^ user.cpp:41:5: error: ‘n’ does not name a type n,x,r,r1,r2,l:longint; ^ user.cpp:43:1: error: ‘procedure’ does not name a type procedure init; ^ user.cpp:44:1: error: ‘begin’ does not name a type begin ^ user.cpp:46:6: error: ‘r2’ does not name a type r2:=0; ^ user.cpp:47:6: error: ‘n’ does not name a type n:=0; ^ user.cpp:48:1: error: ‘end’ does not name a type end; ^ user.cpp:50:1: error: ‘procedure’ does not name a type procedure load; ^ user.cpp:51:1: error: ‘begin’ does not name a type begin