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Cod sursa(job #935185)
#include <fstream>
#include <vector>
#define NMAX 20
#define superMAX 262150
using namespace std;
int cost[NMAX][NMAX], C[superMAX][NMAX];
int N, M;
const int mult = 100000000;
vector<int> smeq[NMAX];
int main()
{
ifstream in("hamilton.in");
ofstream out("hamilton.out");
int i, j, k, a, b, c;
in>>N>>M;
/*for (i=0; i<N; ++i)
for (j=0; j<N; ++j)
cost[i][j] = mult;*/
for (i=0; i<M; ++i)
{
in>>a>>b>>c;
cost[a][b] = c;
smeq[b].push_back(a);
}
for (i=0; i<1<<N; ++i)
for (j=0; j<N; ++j)
C[i][j] = mult;
C[1][0] = 0;
for (i=0; i<1<<N; ++i)
for (j=0; j<N; ++j)
if (i & 1<<j)
for (k=0; k<smeq[j].size(); ++k)
if (i&(1<<smeq[j][k]))
C[i][j] = min(C[i][j], C[i^(1<<j)][smeq[j][k]] + cost[smeq[j][k]][j]);
int result = mult;
for (i=0; i<smeq[0].size(); ++i)
result = min(result, C[(1<<N)-1][smeq[0][i]] + cost[smeq[0][i]][0]);
if (result == mult) out<<"Nu exista solutie"<<endl;
else out<<result<<endl;
return 0;
}