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Cod sursa(job #934898)
#include <fstream>
#define LL long long
using namespace std;
ifstream f("nunta.in"); ofstream g("nunta.out");
int n;
LL a = 1, b = 2, c;
inline LL solve() {
for(int i = 3 ; i <= n; ++i) c = a + b, a = b, b = c;
return c;
}
int main() {
f >> n;
g << solve() << '\n';
g.close();
return 0;
}