Cod sursa(job #931308)
//o(n log n) cu ideea lui francu
#include <iostream>
#include <fstream>
#include <vector>
#include <algorithm>
#define nmax 100005
using namespace std;
int n, m;
vector <int> q;
int v[nmax], h[nmax];
void insert(int i) {
int val = v[i];
int lo = -1;
int hi = q.size();
int mid;
if(q.empty() || val > q[q.size()-1]) {
q.push_back(val);
h[i] = q.size();
return;
}
while(hi - lo > 1) {
mid = lo + (hi - lo) / 2;
if(val >= v[mid]) lo = mid;
else hi = mid;
}
while(val >= q[lo]) lo++;
q[lo] = val;
h[i] = lo + 1;
}
int main() {
ifstream f("scmax.in");
ofstream g("scmax.out");
f>>n;
for(int i=1; i<=n; i++) {
f>>v[i];
insert(i);
//for(int j=0; j<q.size(); j++) cout<<q[j]<<" "; cout<<"\n";
}
int dim = q.size();
g<<dim<<"\n";
cout<<dim<<"\n";
dim = 1;
for(int i=1; i<=n; i++) {
if(h[i] == dim) {
g<<v[h[i]]<<" ";
dim++;
}
//cout<<h[i]<<" ";
}
return 0;
}