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Cod sursa(job #90355)
// O( N )
#include <cstdio>
#define MN (1<<20)
int N, col[MN], next[MN], op[MN][3], repos[MN];
void doit( int A, int B, int C )
{
int last = -1;
for( int i = A; i <= B; i++ )
{
if( !col[i] )
{
if( last == -1 )
{
last = i;
if( i > 0 && col[i-1] )
repos[ i ] = repos[ i - 1 ];
}
else
repos[i] = last;
col[i] = C;
}
else
{
if( last != -1 )
{
next[ last ] = i - 1;
last = -1;
}
i = next[ repos[i] ];
}
}
if( last != -1 )
next[ last ] = B;
}
int main()
{
freopen("curcubeu.in", "r", stdin);
freopen("curcubeu.out", "w", stdout);
int A, B, C;
scanf("%d %d %d %d", &N, &A, &B, &C);
for( int i = 0; i < N - 1; i++ )
next[i] = i;
for( int i = 2 ; i <= N; i++ )
{
if( A > B ){ int aux = A; A = B; B = aux; }
op[i-1][0] = A - 1, op[i-1][1] = B - 1, op[i-1][2] = C;
A = ( (long long)(A) * i ) % N,
B = ( (long long)(B) * i ) % N,
C = ( (long long)(C) * i ) % N;
}
for( int i = N - 1; i >= 1; --i )
doit( op[i][0], op[i][1], op[i][2] );
for( int i = 0; i < N - 1; i++ )
printf("%d\n", col[i]);
return 0;
}