#include <stdio.h>
#include <fstream>
#include <cstring>
using namespace std;

#define in "cast.in"
#define out "cast.out"
#define dim 13

int N, T, Tmin=-1;
int B[dim][8193], L[dim], sir[dim];
bool Sel[8193][dim];
int A[dim][dim];

int Maxim(int,int);
int Ok(int,int);
void Solve();

int main()
{
    int i, k1, j;
    freopen(in,"r",stdin);
    freopen(out,"w",stdout);
    
    memset(Sel,0,sizeof(Sel));
    
    /* Precalculare */
    for ( k1 = 1; k1 <= 8192; k1++ )
    {
        for ( i = 1; i < 13; i++ )
            if ( (k1>>(i-1)) & 1 ) Sel[k1][i] = 1; 
    }
    
    scanf("%d", &T);
    for ( ; T > 0; --T )
    {
        scanf("%d", &N);
        for ( i = 1; i <= N; i++ )
            for ( j = 1; j <= N; j++ )
                scanf("%d", &A[i][j]);
                
        Solve();
    }                
}    

inline int Minim(int a, int b)
{ return (a < b ? a : b); }

inline int Maxim(int a, int b)
{ return (a > b ? a : b); }


int Ok(int k1, int k2)
{
    for ( int i = 1; i <= N; i++ )
        if ( (k2>>(i-1))&1 ) 
             if ( !((k1>>(i-1))&1) ) return 0;
    
    return 1;  
}    

void Solve()
{
    int S = 1<<N;
    S -= 1;
    
    memset(B, 0x3f, sizeof(B) );
    
    for ( int i = 1; i <= N; i++ )
    {
        B[i][ (1<<(i-1)) ] = 0;
    }
   
   /* 20 + TLE
   for ( int k1 = 1; k1 <= S; ++k1 )
    {
        for ( int i = 1; i <= N && 1<<(i-1) <= k1; ++i )
        {
            if ( (k1>>(i-1))&1 == 0 ) continue;
            for ( int k2 = 1; k2 < k1; ++k2 )
            {
                if ( !Ok(k1,k2) ) continue;
                for ( int j = 1; j <= N && 1<<(j-1) <= k2; ++j )
                {
                    if ( (k2>>(j-1))&1 == 0 || i == j ) continue;
                    
                    B[i][k1] = Minim( B[i][k1], A[i][j] + Maxim(B[i][k1-k2],B[j][k2]) ); 
                }             
            }
        }
    }*/
    
    /* 100 */
    
    int k1, i, j, k2, t, Q1;
    int size=0, Q=0;
    
    for ( k1 = 1; k1 <= S; ++k1 ) 
        for ( i = 1; i <= N; ++i )
            if ( Sel[k1][i] )
            {
                 size = 0;
                 
                 for ( j = 1; j <= N; ++j ) // elementele posibile pentru multimie S2
                 {
                     if ( i != j && Sel[k1][j] ) L[++size] = j;  
                 }
                 
                 for ( k2 = 1; k2 < (1<<size); ++k2 ) // 2^size - 1 posibilitati de a lua multimea S2
                 {
                     Q = 0;
                     
                     for ( t = 1; t <= size; ++t )
                     {
                         if ( Sel[k2][t] ) Q += 1<<(L[t]-1);
                     }
                     
                     Q1 = k1 - Q;
                     
                     for ( t = 1; t <= size; ++t )
                         B[i][k1] = Minim( B[i][k1], A[i][L[t]] + Maxim(B[L[t]][Q],B[i][Q1]) ); 
                 }
            }
    
    printf("%d\n", B[1][S]);
}