Pagini recente » Cod sursa (job #2474031) | Cod sursa (job #3287035) | Cod sursa (job #2186596) | Cod sursa (job #2230541) | Cod sursa (job #7284)
Cod sursa(job #7284)
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
float x[1001],y[1001];
int i1,i2,i3,i4,i,sol,n;
float d(int i, int j)
{
float d1,d2;
if (x[i]<x[j]) d1=x[j]-x[i]; else d1=x[i]-x[j];
if (y[i]<y[j]) d2=y[j]-y[i]; else d2=y[i]-y[j];
return (d1*d1)+(d2*d2);
}
void solve()
{
if (d(i1,i4)==d(i2,i3) && d(i3,i4)==d(i1,i2) && d(i1,i2)==d(i2,i3) &&
(d(i1,i3)*d(i1,i3))==(d(i1,i2)*d(i1,i2))+(d(i2,i3)*d(i2,i3)))
++sol;
}
int main()
{
freopen("patrate3.in","r",stdin);
freopen("patrate3.out","w",stdout);
scanf("%d",&n);
for (i=1;i<=n;++i) scanf("%f %f",&x[i],&y[i]);
for (i1=1;i1<=n-3;++i1)
for (i2=i1+1;i2<=n-2;++i2)
for (i3=i2+1;i3<=n-1;++i3)
for (i4=i3+1;i4<=n;++i4)
solve();
printf("%d\n",sol);
return 0;
}