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Cod sursa(job #717225)
#include <fstream>
#include <vector>
#include <queue>
#define nmax 1005
using namespace std;
ifstream f("maxflow.in");
ofstream g("maxflow.out");
int n, m, capacitate[nmax][nmax], flux[nmax][nmax];
int Min, flux_maxim;
int viz[nmax], T[nmax];
queue<int> q;
vector<int> gf[nmax];
void citeste(){
f >> n >> m;
for(int i=1; i<=m; i++){
int x, y, c;//am capacitatea c in conducta x-> y;
f >> x >> y >> c;
gf[x].push_back(y);
capacitate[x][y] = c;
}
}
int bfs(){
for(int i=1; i<=n; i++) viz[i] = 0;
q.push(1);//sursa = 1;
viz[1] = 1;
for(; q.size(); ){
int nod = q.front();
q.pop();
for(int i=0; i<gf[nod].size(); i++){
int vc = gf[nod][i];
if (flux[nod][vc] == capacitate[nod][vc] || viz[vc] == 1) continue;
q.push(vc);
viz[vc] = 1;
T[vc] = nod;
if (vc == n) return 1;//daca ajung la destinatie
}
}
return 0;
}
void rezolva(){
for(; bfs(); ){
//cat timp exista drumuri de crestere aleg minimnul capacitatilor din acel drum;
Min=(1<<29);
for(int i=n; i!=1; i=T[i]){
//am muchia T[i] -> i;
Min = min(Min, capacitate[T[i]][i] - flux[T[i]][i]);
}
for(int i=n; i!=1; i=T[i]){
flux[T[i]][i] += Min;//pe muchia T[i]->i
flux[i][T[i]] -= Min;//pe muchia i->T[i];
//initial flux[i][j] = 0;
}
flux_maxim+= Min;
}
}
void scrie(){
g << flux_maxim << "\n";
}
int main(){
citeste();
rezolva();
scrie();
f.close();
g.close();
return 0;
}