Cod sursa(job #658972)
Utilizator | Data | 9 ianuarie 2012 20:48:47 | |
---|---|---|---|
Problema | Suma divizorilor | Scor | 0 |
Compilator | cpp | Status | done |
Runda | Arhiva de probleme | Marime | 0.37 kb |
#include<fstream.h>
#include<math.h>
int s,m;
long long int nr,a,b;
int main()
{
ifstream f("sumdiv.in");
ofstream g("sumdiv.out");
int i;
f>>a>>b;
nr =(int)pow(a,b);
s+=((int)pow(a,b));
for(i = 1; i <= nr/2; i++)
if(nr%i == 0)
s+=i;
m = (s % 9901);
g<<m;
f.close();
g.close();
return 0;
}