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Cod sursa(job #657690)
#include<fstream>
using namespace std;
ifstream in("distante.in");
ofstream out("distante.out");
int T, N, M, S, D[50005];
void verifica()
{
int i,x,y,c,ok;
ok = 1;
in >> N >> M >> S;
for(i = 1; i <= N; i++)
in >> D[i];
if(D[S])
ok=0;
for(i = 1; i <= M; i++)
{
in >> x >> y >> c;
if(D[x] + c < D[y])
ok = 0;
}
if(ok) out << "DA" << '\n';
else out << "NU" << '\n';
}
int main()
{
in >> T;
for( ; T >0; -- T)
verifica();
return 0;
}