#include <stdio.h>
const int N=100001;

int n,i,j,e[N],x;

int main()
{
    freopen("sum.in","r",stdin);
    freopen("sum.out","w",stdout);
    scanf("%d",&n);
    for (i=1;i<=N;i++)
        e[i]=i;
    for (i=2;i<N;i++)
        if (e[i]==i)
            for (j=i;j<N;j+=i)
                e[j]=e[j]/i*(i-1);
    for(i=1;i<=n;i++)
    {
        scanf("%d",&x);
        printf("%d\n",(e[x]*2)*x);
    }
    return 0;
}