Cod sursa(job #587846)

Utilizator SpiderManSimoiu Robert SpiderMan Data 6 mai 2011 09:44:52
Problema Perb Scor 90
Compilator cpp Status done
Runda Arhiva de probleme Marime 1.94 kb
# include <cstdio>

const char *FIN = "perb.in", *FOU = "perb.out", *adn = { "ACGT" } ;
const int MAX = 605 ;

char S[MAX] ;
int A[MAX][MAX], B[MAX][MAX] ;
int N, M ;

inline int max ( int a, int b ) {
    return (a > b ? a : b) ;
}

inline int min ( int a, int b ) {
    return (a < b ? a : b) ;
}

const int hg = 1 << 13 ;
char ch[hg];
int poz ;

inline void cit (int &x) {
    x = 0;
    if ( ch[0] == '\0' ) fread (ch, 1, hg, stdin);
    else while ( ch[poz] < '0' || ch[poz] > '9' )
            if ( ++poz == hg )
                fread (ch, 1, hg, stdin), poz = 0;

    while ( ch[poz] >= '0' && ch[poz] <= '9' ) {
        x = x * 10 + ch[poz] - '0';
        if ( ++poz == hg )
            fread (ch, 1, hg, stdin), poz = 0;
    }
}

inline void solve ( int K ) {
    int aux, auxdf ;
    for ( int i = N; i ; --i ) {
        for ( int j = 0, see = i + K > N; j < 4; ++j ) {
            B[i][j] = (S[i] == adn[j]) + (see ? 0 : B[i + K][j]) ;
        }
    }

    for ( int i = 1; i <= N; ++i ) {
        for ( int j = i + 2 * K - 1; j <= N; j += K ) {
            aux = 0;
            for ( int k = 0; k < K; ++k ) {
                auxdf = 0 ;
                for ( int l = 0, see = j + k + 1 <= N; l < 4; ++l ) {
                    auxdf = max (auxdf, B[i + k][l] - (see ? B[j + k + 1][l] : 0)) ;
                }
                aux += (j - i + 1) / K - auxdf ;
            }
            A[i][j] = min (A[i][j], aux) ;
        }
    }
}

int main (void) {
    freopen (FIN, "r", stdin) ;
    freopen (FOU, "w", stdout) ;

    scanf ( "%d %d %s", &N, &M, S + 1 ) ;

    for ( int i = 1; i <= N; ++i ) {
        for ( int j = i + 1; j <= N; ++j ) {
            A[i][j] = j - i ;
        }
    }

    for ( int i = 1, j = N >> 1; i <= j; ++i ) {
        solve (i) ;
    }

    cit(N) ;
    for ( int i = 1, x, y; i <= M; ++i ) {
        cit (x), cit(y) ;
        printf ( "%d\n", A[x][y] ) ;
    }
}