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Cod sursa(job #486338)
#include<stdio.h>
#include<vector>
#define inf 2000000000
FILE *f=fopen("dijkstra.in","r");
FILE *g=fopen("dijkstra.out","w");
using namespace std;
int n,m,k,i,x,y,z,j,heapn;
int minim,p;
int s[50001];
int d[50001];
vector< pair<int,int> > a[50001];
void downheap(int p){
//init
int l,r;
while(2*p<=n){
minim=p;
l=2*p;
r=2*p+1;
if(d[minim]>d[l])
minim=l;
if(r<=n&&d[minim]>d[r])
minim=r;
//interschimbam
if(minim!=p){
int t=d[p];
d[p]=d[minim];
d[minim]=t;
}
else break;
}
}
void upheap(int p){
int t;
while(p>1){
t=p/2;
if(d[p]<d[t]){
int m=d[p];
d[p]=d[t];
d[t]=m;
}
else break;
}
}
int main(){
fscanf(f,"%d%d",&n,&m);
//citire
for(i=1;i<=m;i++){
fscanf(f,"%d%d%d",&x,&y,&z);
a[x].push_back(make_pair(y,z));
}
//d=inf
for(i=1;i<=n;i++)
d[i]=inf;
//d[i]= distanta de la nod1 la nodi
for(i=0;i<=a[1].size()-1 ;i++){
heapn++;
d[a[1][i].first]=a[1][i].second;
}
//selectam primul nod
s[1]=1;
//rezolvare N2
for(k=2;k<n;k++){
//reint
minim=inf; p=0;
//cel mai apropiat nod la care se poate ajunge
for(i=1;i<=n;i++)
if( s[i]==0 && d[i]<minim)
{ minim=d[i];
p=i;
}
//selectam nodul
s[p]=1;
//minimul pana la toti vecinii
for(i=0;i<=(int)a[p].size()-1;i++)
if(s[a[p][i].first]==0 && d[p] +a[p][i].second < d[a[p][i].first] )
d[a[p][i].first]=d[p]+a[p][i].second;
}
//afisam
for(i=2;i<=n;i++){
if(d[i]!=inf)
fprintf(g,"%d ",d[i]);
else fprintf(g,"%d ",0);
}
return 0;
}