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Cod sursa(job #404277)
/*
@ Mihai Tabara, 2010
Method: PD
O(n^3) - time
O(N^2) - memory
*/
#include <fstream>
#include <climits>
#include <cstdio>
#include <cstdlib>
using namespace std;
const char* in = "podm.in";
const char* out = "podm.out";
const int NMAX = 505;
const long long INF = LLONG_MAX;
long long Mat ( int i, int j, long long*** ref, long long** P )
{
long long Q;
int k;
if ( (*ref)[i][j] < INF )
return (*ref)[i][j];
if ( i == j )
(*ref)[i][j] = 0;
else
{
for ( k = i; k <= j-1; ++k )
{
Q = Mat ( i, k, ref, P ) + Mat ( k+1, j, ref, P ) + (*P)[i-1] * (*P)[k] * (*P)[j];
if ( Q < (*ref)[i][j] )
(*ref)[i][j] = Q;
}
}
return (*ref)[i][j];
}
int main ( void )
{
freopen ( in, "r", stdin );
freopen ( out, "w", stdout );
int N;
scanf ( "%d", &N );
int i, j;
long long ** M;
long long * P;
M = (long long ** ) calloc ( NMAX, sizeof( long long * ) );
for ( i = 0; i < NMAX; ++i )
M[i] = (long long * ) calloc ( NMAX, sizeof( long long ) );
P = ( long long * ) calloc ( NMAX, sizeof( long long ) );
for ( i = 0; i <= N; scanf ( "%lld", P+i++ ) );
for ( i = 1; i <= N; ++i )
for ( j = 1; j <= N; ++j )
M[i][j] = INF;
printf ( "%lld\n", Mat( 1, N, &M, &P ) );
return 0;
}