Cod sursa(job #395933)
| Utilizator | Data | 14 februarie 2010 02:09:13 | |
|---|---|---|---|
| Problema | Ridicare la putere in timp logaritmic | Scor | 30 |
| Compilator | cpp | Status | done |
| Runda | Arhiva educationala | Marime | 0.43 kb |
#include <stdio.h>
long long n,p;
long long hatvany( long long n, long long p){
long long temp;
if(p==0){return 1;}else{
if(p%2==0){temp=hatvany(n,p/2);
return (temp*temp)%1999999973;}else{
temp=hatvany(n,(p-1)/2);
return n*temp*temp%1999999973;
}}
}
int main(){
freopen("lgput.in","r",stdin);
freopen("lgput.out","w",stdout);
scanf("%lld %lld",&n,&p);
printf("%lld",hatvany(n,p));
return 0;
}