Cod sursa(job #3359641)

Utilizator tamionvTamio Vesa Nakajima tamionv Data 1 iulie 2026 11:38:41
Problema Range minimum query Scor 90
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 4.11 kb
#include <vector>
#include <cassert>
#include <iostream>
#include <algorithm>
#include <fstream>
using namespace std;

class InParser {
private:
	FILE *fin;
	char *buff;
	int sp;

	char read_ch() {
		++sp;
		if (sp == 4096) {
			sp = 0;
			fread(buff, 1, 4096, fin);
		}
		return buff[sp];
	}

public:
	InParser(const char* nume) {
		fin = fopen(nume, "r");
		buff = new char[4096]();
		sp = 4095;
	}

	InParser& operator >> (int &n) {
		char c;
		while (!isdigit(c = read_ch()) && c != '-');
		int sgn = 1;
		if (c == '-') {
			n = 0;
			sgn = -1;
		} else {
			n = c - '0';
		}
		while (isdigit(c = read_ch())) {
			n = 10 * n + c - '0';
		}
		n *= sgn;
		return *this;
	}

	InParser& operator >> (long long &n) {
		char c;
		n = 0;
		while (!isdigit(c = read_ch()) && c != '-');
		long long sgn = 1;
		if (c == '-') {
			n = 0;
			sgn = -1;
		} else {
			n = c - '0';
		}
		while (isdigit(c = read_ch())) {
			n = 10 * n + c - '0';
		}
		n *= sgn;
		return *this;
	}
};

class OutParser {
private:
    FILE *fout;
    char *buff;
    int sp;

    void write_ch(char ch) {
        if (sp == 50000) {
            fwrite(buff, 1, 50000, fout);
            sp = 0;
            buff[sp++] = ch;
        } else {
            buff[sp++] = ch;
        }
    }


public:
    OutParser(const char* name) {
        fout = fopen(name, "w");
        buff = new char[50000]();
        sp = 0;
    }
    ~OutParser() {
        fwrite(buff, 1, sp, fout);
        fclose(fout);
    }

    OutParser& operator << (int vu32) {
        if (vu32 <= 9) {
            write_ch(vu32 + '0');
        } else {
            (*this) << (vu32 / 10);
            write_ch(vu32 % 10 + '0');
        }
        return *this;
    }

    OutParser& operator << (long long vu64) {
        if (vu64 <= 9) {
            write_ch(vu64 + '0');
        } else {
            (*this) << (vu64 / 10);
            write_ch(vu64 % 10 + '0');
        }
        return *this;
    }

    OutParser& operator << (char ch) {
        write_ch(ch);
        return *this;
    }
    OutParser& operator << (const char *ch) {
        while (*ch) {
            write_ch(*ch);
            ++ch;
        }
        return *this;
    }
};

/* This is an O(n) precalculation, O(1) query RMQ implementation.
 * I learned about this method from Andrei-Costin Constantinescu */
template <typename T, T inf, typename Cmp>
class range_min_query{
    Cmp c;
    int n, k;
    std::vector<unsigned long long> msk;
    std::vector<T> buf;

    T& get(int niv, int j){
        return buf[n + (n / 64) * niv + j];
    }

    T small_query(int st, int dr){
        return st >= dr ? inf
            : buf[st + 63 - __builtin_clzll(msk[st] & ((unsigned long long)-1ll >> (64 - dr + st)))];
    }

    T large_query(int st, int dr){
        if(st >= dr) return inf;
        const int niv = 31 - __builtin_clz(dr - st);
        return std::min<T, Cmp>(get(niv, st), get(niv, dr - (1 << niv)), c);
    }
public:
    range_min_query(): n(0), msk(), buf() {}

    template <typename F>
    range_min_query(int N, F f, Cmp C): c(C), n(N), k(31 - __builtin_clz(n / 64)), msk(n + 1, 0), buf(n + (k + 1) * n / 64 + 1){
        for(int i = 0; i < n; ++i) buf[i] = f(i);

        for(int i = n - 1; i >= 0; msk[i--] |= 1)
            for(msk[i] = 2 * msk[i + 1]; msk[i] && !c(buf[i + __builtin_ctzll(msk[i])], buf[i]); )
                msk[i] ^= (msk[i]&-msk[i]);

        for(int i = 0; i + 64 <= n; i += 64) get(0, i / 64) = small_query(i, i + 64);

        for(int niv = 1; niv <= k; ++niv)
            for(int i = 0, j = 1 << (niv - 1); j <= n / 64; ++i, ++j)
                get(niv, i) = std::min<T, Cmp>(get(niv - 1, i), get(niv - 1, j), c);
    }

    T query(int st, int dr){
        return std::min<T, Cmp>({ small_query(st, std::min(st + 64, dr)),
                small_query(std::max(dr - 64, st), dr), 
                large_query((st + 63) / 64, dr / 64) }, c);
    }
};

int main(){
    InParser f("rmq.in");
    OutParser g("rmq.out");
    int n, m;
    f >> n >> m;

    range_min_query<int, 1000000000, less<int>> rmq(n, [&](int){ int x; f >> x; return x; }, less<int>());

    for(int x, y; m; --m){
        f >> x >> y;
        g << rmq.query(x - 1, y) << '\n';
    }
}