Cod sursa(job #3337583)

Utilizator popescumalinaPopescu Malina popescumalina Data 28 ianuarie 2026 20:28:11
Problema Paduri de multimi disjuncte Scor 0
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 2.36 kb
///Varianta 0
/**
#include <iostream>

using namespace std;
const int NMAX = 500;

int N, CC[NMAX + 1];

void Union(int cx, int cy)
{
    for(int i = 1; i <= N; i++)
        if(CC[i] == cy)
        CC[i] = cx;
}

int main()
{
    int M, op, x, y, cx, cy;
    cin >> N >> M;
    for(int i = 1; i <= N; i++)
        CC[i] = i;
    //
    while(M--)
    {
        cin >> op >> x >> y;
        cx = CC[x];
        cy = CC[y];
        if(op == 1)
        {
            if(cx != cy)
                Union(cx, cy);
        }
        else
        {
            if(cx == cy)
                cout << "DA\n";
            else
                cout << "NU\n";
        }
    }
    return 0;
}

///Varianta 1
#include <iostream>

using namespace std;
const int NMAX = 500;

int T[NMAX + 1];

int Find(int i)
{
    if(T[i] == 0)
        return i;
    return T[i] = Find(T[i]);
}

inline void Union(int cx, int cy)
{
    T[cy] = cx;
}

int main()
{
    int N, M, op, x, y, cx, cy;
    cin >> N >> M;
    while(M--)
    {
        cin >> op >> x >> y;
        cx = Find(x);
        cy = Find(y);
        if(op == 1)
        {
            if(cx != cy)
                Union(cx, cy);
        }
        else
        {
            if(cx == cy)
                cout << "DA\n";
            else
                cout << "NU\n";
        }
    }
    return 0;
}
*/

#include <fstream>
#include <iostream>

using namespace std;
const int NMAX = 100001;

int N, M,
       T[NMAX],
       Sz[NMAX];

ifstream f("disjoint.in");
ofstream g("disjoint.out");


int Find(int i)
{
    if(T[i] == 0)
        return i;
    return T[i] = Find(T[i]);
}

inline void Union(int rx, int ry)
{
    if(Sz[rx] < Sz[ry])
    {
        T[rx] = ry;
        Sz[ry] += Sz[rx];
    }
    else
    {
        T[ry] = rx;
        Sz[rx] += Sz[ry];
    }
}

int main()
{
    int cod, x, y, rx, ry;
    f >> N >> M;
    for(int i = 1; i <= N; i++)
        Sz[i] = 1;
    while(M--)
    {
        f >> cod >> x >> y;
        rx = Find(x);
        ry = Find(y);
        if(cod == 1)
        {
                Union(rx, ry);
        }
        else
        {
            if(rx == ry)
                cout << "DA\n";
            else
                cout << "NU\n";
        }
    }
    f.close();
    g.close();
    return 0;
}