Compilare: main.cpp: In function 'void showdg(int)': main.cpp:14:5: warning: this 'for' clause does not guard... [-Wmisleading-indentation] 14 | for(int b = base / 10; b >= 1; b /= 10) | ^~~ main.cpp:15:30: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for' 15 | out<<((x / b) % 10); return; | ^~~~~~ main.cpp: In member function 'void biggint::operator=(int)': main.cpp:22:9: warning: this 'for' clause does not guard... [-Wmisleading-indentation] 22 | for(int i = 1; i <= x[0]; i++) x[i] = 0; x[0] = 0; | ^~~ main.cpp:22:50: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for' 22 | for(int i = 1; i <= x[0]; i++) x[i] = 0; x[0] = 0; | ^ main.cpp: In member function 'void biggint::operator=(const biggint&)': main.cpp:28:9: warning: this 'for' clause does not guard... [-Wmisleading-indentation] 28 | for(int i = 1; i <= x[0]; i++) x[i] = 0; x[0] = 0; | ^~~ main.cpp:28:50: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for' 28 | for(int i = 1; i <= x[0]; i++) x[i] = 0; x[0] = 0; | ^ main.cpp: In member function 'void biggint::show()': main.cpp:42:9: warning: this 'for' clause does not guard... [-Wmisleading-indentation] 42 | for(int i = x[0] - 1; i >= 1; i--) | ^~~ main.cpp:43:27: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for' 43 | showdg(x[i]); out<<"\n"; | ^~~