Cod sursa(job #3195570)

Utilizator Ionut2791Voicila Ionut Marius Ionut2791 Data 21 ianuarie 2024 11:49:08
Problema Ciclu Eulerian Scor 100
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 2.92 kb
#include "bits/stdc++.h"
#include <type_traits>
using namespace std;

#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization("unroll-loops")

// ============ Macros starts here ============
int recur_depth = 0;
#ifdef DEBUG
#define dbg(x) {++recur_depth; auto x_=x; --recur_depth; cerr<<string(recur_depth, '\t')<<"\e[91m"<<__func__<<":"<<__LINE__<<"\t"<<#x<<" = "<<x_<<"\e[39m"<<endl;}
#else
#define dbg(x)
#endif // DEBUG
template<typename Ostream, typename Cont>
typename enable_if<is_same<Ostream, ostream>::value, Ostream&>::type operator<<(Ostream& os, const Cont& v) {
    os << "[";
    for (auto& x : v) { os << x << ", "; }
    return os << "]";
}
template<typename Ostream, typename ...Ts>
Ostream& operator<<(Ostream& os, const pair<Ts...>& p) {
    return os << "{" << p.first << ", " << p.second << "}";
}

#define readFast                      \
    ios_base::sync_with_stdio(false); \
    cin.tie(0);                       \
    cout.tie(0);
#ifdef LOCAL
#define read() ifstream fin("date.in.txt")
#else
#define read() readFast
#endif // LOCAL
// ============ Macros ends here ============

#define fin cin
#define ll long long
#define sz(x) (int)(x).size()
#define all(v) v.begin(), v.end()
#define output(x) (((int)(x) && cout << "YES\n") || cout << "NO\n")
#define LSB(x) (x & (-x))
#define test cout << "WORKS\n";

const int N = 1e5 + 15;
const int MOD = 1e9 + 7; // 998244353

const int INF = 1e9;
int t, n, m;

// vector<int> graf[N];
vector<pair<int, int>> graf[N];
// multiset<pair<int, int>> used;
vector<int> ans;
vector<int> dg;
bool used[N * 5];


int main() {
    read();
    ifstream fin("ciclueuler.in");
    ofstream cout("ciclueuler.out");
    fin >> n >> m;

    dg.resize(n + 1);
    for (int i = 0; i < m; ++i) {
        int a, b;
        fin >> a >> b;
        graf[a].push_back({ b, i });
        graf[b].push_back({ a, i });
        ++dg[a];
        ++dg[b];
    }
    for (int i = 1; i <= n; ++i) {
        if (dg[i] % 2 == 1) {
            cout << -1 << '\n';
            return 0;
        }
    }

    stack<int> stk;
    stk.push(1);
    while (!stk.empty()) {
        int node = stk.top();

        while (!graf[node].empty() && used[graf[node].back().second]) {
            graf[node].pop_back();
        }

        if (graf[node].empty()) {
            stk.pop();
            ans.push_back(node);
            continue;
        }
        int to = graf[node].back().first;
        int i = graf[node].back().second;
        graf[node].pop_back();
        used[i] = true;
        stk.push(to);
    }
    ans.pop_back();
    for (int x : ans) {
        cout << x << " ";
    }

    return 0;
} /*stuff you should look for !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
   * test the solution with the given example
   * int overflow, array bounds, matrix bounds
   * special cases (n=1?)
   * do smth instead of nothing and stay organized
   * WRITE STUFF DOWN
   * DON'T GET STUCK ON ONE APPROACH
~Benq~*/