Cod sursa(job #3189201)

Utilizator NeganAlex Mihalcea Negan Data 4 ianuarie 2024 17:26:02
Problema Flux maxim Scor 40
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 1.91 kb
#include <bits/stdc++.h>

using namespace std;

ifstream fin("maxflow.in");
ofstream fout("maxflow.out");

int n, maxFlow = 0, m;
int viz[1005];
int aug_path[1005];
int last[1005];

struct elem
{
    int node, cap, flow;
};
vector<elem>V[1005];
pair<int, int>rezidual[1005][1005];


bool BFS(int node)
{
    for(int i = 1;i <= n;i++)
        last[i] = viz[i] = aug_path[i] = 0;
    queue<int>q;
    q.push(node);
    viz[node] = 1;
    while(!q.empty())
    {
        int nod = q.front();
        q.pop();
        for(auto x : V[nod])
            if(viz[x.node] == 0 && (rezidual[nod][x.node].first - rezidual[nod][x.node].second) > 0 )
            {
                viz[x.node] = 1;
                last[x.node] = nod;
                q.push(x.node);
            }
    }
    int nod = n, cnt = 0;
    aug_path[++cnt] = nod;
    while(last[nod] != 0)
    {
        //cout << nod << " ";
        aug_path[++cnt] = last[nod];
        nod = last[nod];
    }
    if(cnt <= 1)
        return false;
    reverse(aug_path + 1, aug_path + cnt + 1);
    int bottleneck = 1e9;
    for(int i = 1;i < cnt;i++)
    {
        int x = aug_path[i];
        int y = aug_path[i + 1];
        bottleneck = min(bottleneck, rezidual[x][y].first - rezidual[x][y].second);
    }
    for(int i = 1;i < cnt;i++)
    {

        int x = aug_path[i];
        int y = aug_path[i + 1];
        rezidual[x][y].second += bottleneck;
        rezidual[y][x].second -= bottleneck;
    }
    maxFlow += bottleneck;
    return true;
}

void Solve()
{
    fin >> n >> m;
    for(int i = 1;i <= m;i++)
    {
        int x, y, c;
        fin >> x >> y >> c;
        V[x].push_back({y, c, 0});
        V[y].push_back({x, 0, 0});
        rezidual[x][y] = {c, 0};
        rezidual[y][x] = {0, 0};
    }
    while(BFS(1))
        ;
    fout << maxFlow << "\n";
}
int main()
{
    Solve();
    return 0;
}