// evaluare de expresii cu operanzi de prioritati diferite(+, -, *, /, ...)
//problema pe infoarena

// expresie -> termen -> factor -> expresie || numar
#include <bits/stdc++.h>
#define nmax 100005
using namespace std;
char s[nmax];
int i;
int expresie();
int termen();
int factor();
int numar();
int expresie()   // rezolvarea problemei
{
    int r = termen();
    while(s[i] == '+' || s[i] == '-')
    {
        if(s[i] == '+')
        {
            i++; // sarim peste ca dupa oricum adunam
            r += termen();
        }
        else
        {
            i++; // sarim peste
            r -= termen();
        }
    }
    return r;
}
int termen()
{
    int r = factor();
    while(s[i] == '*' || s[i] == '/')
    {
        if(s[i] == '*')
        {
            i++;
            r *= factor();
        }
        else
        {
            i++;
            r /= factor();
        }
    }
    return r;
}
int factor()
{
    int r;
    if(s[i] == '(')
    {
        i++;  // sari peste deschisa
        r = expresie();  // evaluezi ce e in interior
        i++;  // sari si peste asta
    }
    else
    {
        r = numar();
    }
    return r;
}
int numar()
{
    int r = 0;
    while(s[i] >= '0' && s[i] <= '9')
    {
        r = r * 10 + s[i] - '0';
        i++;
    }
    return r;
}
ifstream fin("evaluare.in");
ofstream fout("evaluare.out");
signed main()
{
    fin >> s;
    int i = 0;
    fout << expresie();
    return 0;
}