Cod sursa(job #2907820)

Utilizator Alexandru_OlteanuAlexandru Olteanu Alexandru_Olteanu Data 31 mai 2022 17:45:08
Problema Problema rucsacului Scor 100
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 2.21 kb
/*
    Programmer : Alexandru Olteanu
*/
#include<bits/stdc++.h>
using namespace std;
// GCC Optimizations
// #pragma GCC optimize("Ofast");
// #pragma GCC target("fma,sse,sse2,sse3,ssse3,sse4,popcnt")
// #pragma GCC target("abm,mmx,avx,avx2,tune=native")
// #pragma GCC optimize(3)
// #pragma GCC optimize("inline")
// #pragma GCC optimize("-fgcse")
// #pragma GCC optimize("-fgcse-lm")
// #pragma GCC optimize("-fipa-sra")
// #pragma GCC optimize("-ftree-pre")
// #pragma GCC optimize("-ftree-vrp")
// #pragma GCC optimize("-fpeephole2")
// #pragma GCC optimize("-ffast-math")
// #pragma GCC optimize("-fsched-spec")
// #pragma GCC optimize("unroll-loops")
// Useful
mt19937 rng((unsigned int) chrono::steady_clock::now().time_since_epoch().count());
#define FastEverything  ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define HighPrecision cout<<fixed<<setprecision(17);
typedef long long ll;
typedef pair<int,int> pii;
ll const mod=1000000007LL;
ll const mod2 = 100000000LL;
ll const md=998244353LL;
ll mypowr(ll a,ll b, ll mod1) {ll res=1;if(b<0)b=0;a%=mod1; assert(b>=0);
for(;b;b>>=1){if(b&1)res=res*a%mod1;a=a*a%mod1;}return res;}
ll mypow(ll a,ll b) {ll res=1;if(b<0)b=0;assert(b>=0);
for(;b;b>>=1){if(b&1)res=res*a;a=a*a;}return res;}
#define pb push_back
#define fi first
#define se second
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(), x.rend()

ifstream in("rucsac.in");
ofstream out("rucsac.out");
#define cin in
#define cout out

const ll infll = 9e18;
const int inf = 2e9;
const ll maxn = 1e4 + 5;

int w[maxn], p[maxn];
int dp[2][maxn];

int main()
{
    FastEverything
    HighPrecision

    int test = 1;
    // cin >> test;
    for (int tt = 1; tt <= test; ++tt) {
        int n, k;
        cin >> n >> k;
        for (int i = 1; i <= n; ++i) {
            cin >> w[i] >> p[i];
        }
        for (int i = 1; i <= n; ++i) {
            for (int j = 0; j <= k; ++j) {
                dp[i % 2][j] = dp[1 - i % 2][j];
                if (w[i] <= j) {
                    dp[i % 2][j] = max(dp[i % 2][j], dp[1 - i % 2][j - w[i]] + p[i]); 
                }
            }
        }
        cout << dp[n % 2][k] << '\n';

    }

    return 0;
}