#include <iostream>
#include <fstream>
#include <vector>
#include <map>
#include <queue>
using namespace std;
 
ifstream fin("dijkstra.in");
ofstream fout("dijkstra.out");
 
const int MAX_SIZE = 50005;
const int MAX_SUM = 1000000001;
 
vector<int> graph[MAX_SIZE];
int costs[MAX_SIZE][MAX_SIZE];
int distances[MAX_SIZE];
 
void findMinimumCosts(int peaks) {
    for (int i = 2; i <= peaks; ++i) {
        distances[i] = MAX_SUM; // initializam distantele pentru fiecare punct
    }
    queue<int> positions;
    positions.push(1);
    while (!positions.empty()) {
        int currentPoint = positions.front();
        positions.pop();
        for (int i = 0; i < graph[currentPoint].size(); ++i) {
            int nextPoint = graph[currentPoint][i];
            distances[nextPoint] = min(distances[nextPoint], distances[currentPoint] + costs[currentPoint][nextPoint]);
            positions.push(nextPoint);
        }
    }
    for (int i = 2; i <= peaks; ++i) {
        if (distances[i] == MAX_SUM) {
            fout << 0 << " ";
        } else {
            fout << distances[i] << " ";
        }
    }
}

int main() {
    int peaks, arches;
    fin >> peaks >> arches;
    for (int i = 1; i <= arches; ++i) {
        int start, end, cost;
        fin >> start >> end >> cost;
        graph[start].push_back(end);
        costs[start][end] = cost; // costurile arcelor
    }
    findMinimumCosts(peaks);
    return 0;
}
 /*
  
  1 ≤ N ≤ 50 000
  1 ≤ M ≤ 250 000
  Lungimile arcelor sunt numere naturale cel mult egale cu 20 000.
  Pot exista arce de lungime 0
  Nu exista un arc de la un nod la acelasi nod.
  Daca nu exista drum de la nodul 1 la un nod i, se considera ca lungimea minima este 0.
  Arcele date in fisierul de intrare nu se repeta.
  
  50000 7
  1 2 1
  2 3 2
  3 4 3
  4 5 1
  1 5 700
  2 5 100
  3 5 30 -> 1 3 5 7 + multe 0-uri
  
  5 7
  1 2 1
  2 3 2
  3 4 3
  4 5 1
  1 5 700
  2 5 100
  3 5 30 -> 1 3 6 7
  
  5 3
  1 5 2
  1 4 5
  5 4 1 -> 0 0 3 2
  
  5 3
  1 5 2
  1 4 3
  5 4 1 -> 0 0 3 2
  
  
  3 1
  1 2 1 -> 1 0
  
  4 4
  1 2 1
  1 3 2
  3 4 1
  2 4 1 -> 1 2 2
  
  
  5 6
  1 2 1
  1 4 2
  4 3 4
  2 3 2
  4 5 3
  3 5 6 -> 1 3 2 5
  
  
  
  */