Cod sursa(job #2813589)

Utilizator divadddDavid Curca divaddd Data 6 decembrie 2021 23:07:11
Problema Bool Scor 60
Compilator cpp-64 Status done
Runda Arhiva de probleme Marime 2.17 kb
#include <iostream>
#include <fstream>
#define MAX 1004
using namespace std;
char s[MAX],c;
bool valori[30]; /// v[0] = valoarea lui a, v[1] = al lui b, ..., a[25] = al lui z
int n,i;

ifstream fin("bool.in");
ofstream fout("bool.out");

bool expresie();
bool or_operatie();
bool and_operatie();

int main()
{
    fin.getline(s, 1002); /// -1, pt mai trebuie si \0 de la final
    fin >> n;
    for(int i = 0; i <= 26; i++){
        valori[i] = false;
    }
    for(int j = 1; j <= n; j++){
        fin >> c;
        i = 0; /// aici era bugul ;D
        /// cand re-evaluam expresia i era deja la 32
        /// dar i mai era si variabila din for
        valori[c-'A'] = !valori[c-'A'];
        fout << or_operatie();
    }
    return 0;
}

/**
proritate: - or
           - and
           - expresie
or = and or and
and = exp and exp
exp = 1. un alt or
      2. TRUE / FALSE
      3. alta variabila
      4. NOT exp
**/

bool and_operatie(){
    bool r = expresie(); /// setam true defaultu
    if(s[i] == ' '){
        i++;
    }
    while(s[i] == 'A' && s[i+1] == 'N'){
        i += 3; /// trecem peste ND si un spatiu
        r = (r && expresie());
    }
    return r;
}

bool or_operatie(){
    bool r = and_operatie(); /// setam true defaultu
    if(s[i] == ' '){
        i++;
    }
    while(s[i] == 'O' && s[i+1] == 'R'){
        i += 2; /// trecem peste R si un spatiu
        r = (r || and_operatie());
    }
    return r;
}

bool expresie(){
    bool r = true;
    if(s[i] == ' '){
        i++;
    }else if(s[i] == '('){
        i++;
        r = or_operatie();
        i++;
    }else if(s[i] == ')'){
        i++;
    }else{
        if(s[i] == 'N' && s[i+1] == 'O'){
            /// NOT
            i += 3; /// trecem peste OT si un spatiu
            r = !(expresie());
        }else if(s[i] == 'T' && s[i+1] == 'R'){
            i += 4; /// trecem peste RUE si un spatiu
            r = true;
        }else if(s[i] == 'F' && s[i+1] == 'A'){
            i += 5; /// trecem peste ALSE si un spatiu
            r = false;
        }else{
            r = valori[s[i]-'A'];
            i++;
        }
    }
    return r;
}