Pagini recente » Cod sursa (job #1770387) | Cod sursa (job #990857) | Cod sursa (job #2222911) | Cod sursa (job #1432094) | Cod sursa (job #2788000)
#include <fstream>
#include <climits>
#include <vector>
#include <queue>
#include <set>
#include <stack>
#include <cstring>
#include<algorithm>
using namespace std;
int n,q;
int a[100001][390];
ifstream fin("rmq.in");
ofstream fout("rmq.out");
void calc()
{
for (int j = 1; 1 << j <= n; j++)
{
for (int i = 1; i + (1 << j) - 1 <= n; i++)
{
//secventa de la i la i+1<<j are minimul
//egal cu minimul de la i si secv 1<<(j-1) si i+1<<(j-1)
//concret pt indicele 4 luat de secv 2 avem minimul de la 4 si minimul de la 4+1 ambele luate de lungime 1
a[i][j] = min(a[i][j - 1], a[i + 1 << (j - 1)][j - 1]);
}
}
}
int query(int L, int R)
{
int lung = R - L + 1;
//calculez cea mai mare pputere de 2 care incape in lung;
int k = 1, nrLog = 0;
while (k <= lung)
{
nrLog++;
k *= 2;
}
k = k / 2;
nrLog--;
return min(a[L][nrLog], a[R - k + 1][nrLog]);
}
int main()
{
fin >> n >> q;
for (int i = 1; i <= n; i++)
{
fin >> a[i][0];
}
calc();
for (int i = 1; i <= q; i++)
{
int x, y;
fin >> x >> y;
fout << query(x, y)<<"\n";
}
return 0;
}