Pagini recente » Cod sursa (job #1095775) | Cod sursa (job #3259563) | Cod sursa (job #601624) | Cod sursa (job #1242848) | Cod sursa (job #2764252)
#include <iostream>
#include <string.h>
#include <random>
#include <fstream>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <iomanip>
#include <algorithm>
#include <math.h>
#include <cmath>
#include <vector>
#include <stack>
#include <queue>
#include <bitset>
#include <map>
#include <set>
#include <unordered_map>
#include <unordered_set>
#include <complex>
//#include <ext/pb_ds/assoc_container.hpp>
//using namespace __gnu_pbds;
using namespace std;
typedef pair<int, int> pii;
typedef pair<int, string> pis;
typedef pair<string, string> pss;
typedef pair<int, char> pic;
typedef pair<pii, int> piii;
typedef pair<double, double> pdd;
typedef long long ll;
typedef unsigned long long ull;
typedef unsigned int uint;
typedef pair<ll, ll> pll;
typedef pair<int, ll> pil;
typedef pair<ull, ull> pull;
typedef complex<double> cd;
//#define max(n, m) ((n>m)?n:m)
//#define min(n, m) ((n<m)?n:m)
#define f first
#define s second
#define input() ios_base::sync_with_stdio(0);cin.tie(0);
ifstream fin("critice.in");
ofstream fout("critice.out");
vector<int> adj[510];
queue<int> nextInLine;
bitset<510> visited;
int cur[510][510], lim[510][510], par[510];
vector<int> v;
vector<pii> edges;
int main()
{
int n, m, a, b, c, curN, curF, ans = 0;
fin >> n >> m;
for(int i = 0; i < m; i ++)
{
fin >> a >> b >> c; a--; b--;
adj[a].push_back(b); adj[b].push_back(a);
lim[a][b] += c; lim[b][a] += c;
edges.push_back({a, b});
}
par[0] = -1;
while(true)
{
nextInLine.push(0);
visited.reset(); visited[0] = true;
while(!nextInLine.empty())
{
curN = nextInLine.front();
nextInLine.pop();
if(curN == n-1) continue;
for(auto it : adj[curN])
if(cur[curN][it] != lim[curN][it] && !visited[it])
{
nextInLine.push(it);
visited[it] = true;
par[it] = curN;
}
}
if(!visited[n-1])
{
for(int i = 0; i < edges.size(); i ++)
if(visited[edges[i].f] ^ visited[edges[i].s])
v.push_back(i+1);
break;
}
for(auto it : adj[n-1])
{
if(!visited[it] || cur[it][n-1] == lim[it][n-1]) continue;
curF = 2000000000; par[n-1] = it; curN = n-1;
while(curN != 0)
{
curF = min(curF, lim[par[curN]][curN] - cur[par[curN]][curN]); curN = par[curN];
}
curN = n-1;
while(curN != 0)
{
cur[par[curN]][curN] += curF; cur[curN][par[curN]] -= curF; curN = par[curN];
}
ans += curF;
}
}
fout << v.size() << "\n";
for(int i = 0; i < v.size(); i ++)
fout << v[i] << "\n";
}