#include <bits/stdc++.h>
#define ll long long
#define nl '\n'
#define FOR(i, a, b) for (int i = a; i <= b; ++i)
#define F0R(i, a, b) for (int i = a; i >= b; --i)
#define FORd(i, n) for (int i = 0; i < n; ++i)
#define F0Rd(i, n) for (int i = n - 1; i >= 0; --i)
#define trav(a, x) for (auto &a : x)
#define uid(a, b) uniform_int_distribution<int>(a, b)(rng)
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int mxN = 1e5 + 5;
int MaxArb[4 * mxN], N, Q;
ifstream fin("aib.in");
ofstream fout("aib.out");
void Update(int node, int Pos, int Left, int Right, int value) {
if (Left == Right) {
MaxArb[node] += value;
return;
}
int mij = (Left + Right) / 2;
if (mij >= Pos) {
Update(2 * node, Pos, Left, mij, value);
}
else {
Update(2 * node + 1, Pos, mij + 1, Right, value);
}
MaxArb[node] = MaxArb[2 * node] + MaxArb[2 * node + 1];
}
void Query(int node, int Left_req, int Right_req, int Left, int Right, int &sum) {
if (Left_req <= Left && Right <= Right_req) {
sum += MaxArb[node];
return;
}
int mij = (Left + Right) / 2;
if (mij >= Left_req) {
Query(2 * node, Left_req, Right_req, Left, mij, sum);
}
if (mij < Right_req) {
Query(2 * node + 1, Left_req, Right_req, mij + 1, Right, sum);
}
}
void solve() {
fin >> N >> Q;
for (int i = 1; i <= N; ++i) {
int x;
fin >> x;
Update(1, i, 1, N, x);
}
while (Q--) {
int op, a, b;
fin >> op;
if (op == 2) {
fin >> a;
for (int i = 1; i <= N; ++i) {
int sum = 0;
Query(1, 1, i, 1, N, sum);
if (sum == a) {
fout << i;
a = -1;
break;
}
}
if (a != -1) {
fout << -1;
}
}
else if (op == 0) {
fin >> a >> b;
Update(1, a, 1, N, b);
}
else {
fin >> a >> b;
int sum = 0;
Query(1, a, b, 1, N, sum);
fout << sum;
}
fout << nl;
}
}
int main() {
fin.tie(0); fout.tie(0);
ios::sync_with_stdio(0);
int T = 1;
// cin >> T;
while (T--) {
solve();
}
return 0;
}
//read the question correctly (ll vs int)
//what's the meaning of the problem ? Think outside the BOX !!!
//edge cases ?
//make it simple
//write everything (observations, edge cases, ideas, steps, methods, ...)