#include <bits/stdc++.h>
#define ll long long
#define nl '\n'
#define FOR(i, a, b) for (int i = a; i <= b; ++i)
#define F0R(i, a, b) for (int i = a; i >= b; --i)
#define FORd(i, n) for (int i = 0; i < n; ++i)
#define F0Rd(i, n) for (int i = n - 1; i >= 0; --i)
#define trav(a, x) for (auto &a : x)
#define uid(a, b) uniform_int_distribution<int>(a, b)(rng)
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int mxN = 1e5 + 5;
const int MOD = 1e9 + 7;
ifstream fin("arbint.in");
ofstream fout("arbint.out");
int MaxArb[2 * mxN];
void Update(int Pos, int nod, int left, int right, int value) {
if (left == right) {
MaxArb[nod] = value;
return;
}
int mij = (left + right) / 2;
if (Pos <= mij) {
Update(Pos, 2 * nod, left, mij, value);
}
else {
Update(Pos, 2 * nod + 1, mij + 1, right, value);
}
MaxArb[nod] = max(MaxArb[2 * nod], MaxArb[2 * nod + 1]);
}
void Query(int nod, int req_left, int req_right, int left, int right, int &maxim) {
if (req_left <= left && right <= req_right) {
maxim = max(maxim, MaxArb[nod]);
return;
}
int mij = (left + right) / 2;
if (mij >= req_left) {
Query(2 * nod, req_left, req_right, left, mij, maxim);
}
if (mij < req_right) {
Query(2 * nod + 1, req_left, req_right, mij + 1, right, maxim);
}
}
void solve() {
int N, Q;
fin >> N >> Q;
FOR(i, 1, N) {
int x; fin >> x;
Update(i, 1, 1, N, x);
}
while (Q--) {
int op, a, b;
fin >> op >> a >> b;
if (op == 1) {
Update(a, 1, 1, N, b);
}
else {
int maxim = -1;
Query(1, a, b, 1, N, maxim);
fout << maxim << nl;
}
}
}
int main() {
fin.tie(0); fout.tie(0);
ios::sync_with_stdio(0);
int T = 1;
// cin >> T;
while (T--) {
solve();
}
return 0;
}
//read the question correctly (ll vs int)
//what's the meaning of the problem ? Think outside the BOX !!!
//edge cases ?
//make it simple
//write everything (observations, edge cases, ideas, steps, methods, ...)