Cod sursa(job #2758451)

Utilizator BogdanFarcasBogdan Farcas BogdanFarcas Data 10 iunie 2021 15:39:17
Problema Algoritmul lui Dijkstra Scor 100
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 2.05 kb
#include <fstream>
#include <vector>

using namespace std;

const int N = 50001;
const int INF = 1e9 + 1;

struct succesor
{
    int vf, c;
};

int d[N], h[N], poz[N], n, m, nh;
vector <succesor> s[N];

void schimba(int p, int q)
{
    swap(h[p], h[q]);
    poz[h[p]] = p;
    poz[h[q]] = q;
}

void urca(int p)
{
    while (p > 1 && d[h[p]] < d[h[p/2]])
    {
        schimba(p, p/2);
        p /= 2;
    }
}

void coboara(int p)
{
    int fs = 2*p, fd = 2*p + 1, optim = p;
    if (fs <= nh && d[h[fs]] < d[h[optim]])
    {
        optim = fs;
    }
    if (fd <= nh && d[h[fd]] < d[h[optim]])
    {
        optim = fd;
    }
    if (optim != p)
    {
        schimba(p, optim);
        coboara(optim);
    }
}

void sterge(int p)
{
    if (p == nh)
    {
        nh--;
    }
    else
    {
        schimba(p, nh);
        poz[h[nh--]] = -1;
        urca(p);//nu se va intampla daca p = 1
        coboara(p);
    }
}

void dijkstra(int x0)
{
    //initializam vectorul d
    for (int i = 1; i <= n; i++)
    {
        d[i] = INF;
        h[++nh] = i;
        poz[i] = nh;
    }
    d[x0] = 0;
    urca(poz[x0]);
    while (nh > 0)//cat timp heap-ul nu e vid
    {
        int x = h[1];//varful cu distanta de la x0 la el minima
        sterge(1);
        for (auto p: s[x])
        {
            int y = p.vf;
            int c = p.c;
            if (d[x] + c < d[y])
            {
                d[y] = d[x] + c;
                //pred[y] = x; daca as vrea sa refac drumurile
                urca(poz[y]);
            }
        }
    }
}

int main()
{
    ifstream in("dijkstra.in");
    ofstream out("dijkstra.out");
    in >> n >> m;
    for (int i = 0; i < m; i++)
    {
        int x, y, c;
        in >> x >> y >> c;
        s[x].push_back((succesor){y, c});
    }
    in.close();
    dijkstra(1);
    for (int i = 2; i <= n; i++)
    {
        if (d[i] == INF)
        {
            d[i] = 0;
        }
        out << d[i] << " ";
    }
    out.close();
    return 0;
}