Borderou de evaluare (job #2753511)
Utilizator | Data | 23 mai 2021 10:20:28 | |
---|---|---|---|
Problema | Oz | Status | done |
Runda | Arhiva de probleme | Compilator | cpp-64 | Vezi sursa |
Scor | 0 |
Raport evaluator
Eroare de compilare:
main.cpp:5:71: error: 'int div [10002]' redeclared as different kind of symbol
int j,k,f[50000],n,m,i,a,b,sol,v1[10002],v[10002],r,o[10002],div[10002];
^
In file included from /usr/include/c++/6/cstdlib:75:0,
from /usr/include/c++/6/ext/string_conversions.h:41,
from /usr/include/c++/6/bits/basic_string.h:5420,
from /usr/include/c++/6/string:52,
from /usr/include/c++/6/bits/locale_classes.h:40,
from /usr/include/c++/6/bits/ios_base.h:41,
from /usr/include/c++/6/ios:42,
from /usr/include/c++/6/istream:38,
from /usr/include/c++/6/fstream:38,
from main.cpp:1:
/usr/include/stdlib.h:788:14: note: previous declaration 'div_t div(int, int)'
extern div_t div (int __numer, int __denom)
^~~
main.cpp: In function 'int main()':
main.cpp:11:33: error: invalid types '<unresolved overloaded function type>[int]' for array subscript
cin >>v[i]>>v1[i]>>div[i];
^
main.cpp:10:5: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
for (i=1; i<=m; i++)
^~~
main.cpp:12:9: note: ...this statement, but the latter is misleadingly indented as if it is guarded by the 'for'
for (i=1; i<=n; i++)
^~~
main.cpp:17:16: error: invalid types '<unresolved overloaded function type>[int]' for array subscript
b=div[i];
^
main.cpp:25:36: error: invalid types '<unresolved overloaded function type>[int]' for array subscript
o[v[i]]=o[v[i]]/a*div[i];
^
main.cpp:27:20: error: invalid types '<unresolved overloaded function type>[int]' for array subscript
b=div[i];
^
main.cpp:34:32: error: invalid types '<unresolved overloaded function type>[int]' for array subscript
o[v[i]]=o[v[i]]/a*div[i];
^
main.cpp:46:20: error: invalid types '<unresolved overloaded function type>[int]' for array subscript
if(a==div[i])
^
main.cpp:48:25: error: invalid types '<unresolved overloaded function type>[int]' for array subscript
else if(a!=div[i])
^
Non zero exit status: 1
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