#include <fstream>
using namespace std;

ifstream fin("ciur.in");
ofstream fout("ciur.out");

int a[2000000];

void Ciur(int n)
{
    int nr = 0;
    for (int i = 4; i <= n; i += 2)
    {
      nr++;
      a[i] = 1;
    }

    for (int i = 3; i*i <= n; i += 2)
      if (a[i] == 0)
        for (int j = i*i; j <= n; j += 2*i)
        {
          nr++;
          a[j] = 1;
        }

      fout << n - nr - 1;
}

int main()
{
    int n;
    fin >> n;

    Ciur(n);

    fin.close();
    fout.close();
    return 0;
}