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#include <bits/stdc++.h>
using namespace std;
class InParser {
private:
FILE *fin;
char *buff;
int sp;
char read_ch() {
++sp;
if (sp == 4096) {
sp = 0;
fread(buff, 1, 4096, fin);
}
return buff[sp];
}
public:
InParser(const char* nume) {
fin = fopen(nume, "r");
buff = new char[4096]();
sp = 4095;
}
InParser& operator >> (int &n) {
char c;
while (!isdigit(c = read_ch()) && c != '-');
int sgn = 1;
if (c == '-') {
n = 0;
sgn = -1;
} else {
n = c - '0';
}
while (isdigit(c = read_ch())) {
n = 10 * n + c - '0';
}
n *= sgn;
return *this;
}
};
class OutParser {
private:
FILE *fout;
char *buff;
int sp;
void write_ch(char ch) {
if (sp == 50000) {
fwrite(buff, 1, 50000, fout);
sp = 0;
buff[sp++] = ch;
} else {
buff[sp++] = ch;
}
}
public:
OutParser(const char* name) {
fout = fopen(name, "w");
buff = new char[50000]();
sp = 0;
}
~OutParser() {
fwrite(buff, 1, sp, fout);
fclose(fout);
}
OutParser& operator << (int vu32) {
if (vu32 <= 9) {
write_ch(vu32 + '0');
} else {
(*this) << (vu32 / 10);
write_ch(vu32 % 10 + '0');
}
return *this;
}
OutParser& operator << (char ch) {
write_ch(ch);
return *this;
}
OutParser& operator << (const char *ch) {
while (*ch) {
write_ch(*ch);
++ch;
}
return *this;
}
};
InParser fin("overlap.in");
OutParser fout("overlap.out");
struct pair_hash {
template<class T1, class T2>
size_t operator() (const pair<T1, T2> &p) const {
return hash<T1>()(p.first)^hash<T2>()(p.second);
}
};
const int NMAX = 808;
int N, x, y, prv[NMAX], nxt[NMAX], sol[NMAX];
pair<int,int> p[NMAX], init[NMAX];
unordered_map<pair<int,int>,int,pair_hash> match;
int main() {
fin >> N;
for(int i = 1; i <= N; ++i) {
fin >> x >> y;
init[i] = p[i] = make_pair(x, y);
match[init[i]] = i;
}
// rotatie trigonometrica la 90 de grade: (-y, x)
// rotatie in sensul acelor de ceasornic la 90 de grade: (y, -x)
for(int rep = 0; rep < 4; ++rep) {
for(int i = 1; i <= N; ++i) {
swap(p[i].first, p[i].second);
p[i].second *= -1;
}
for(int i = 2; i <= N; ++i) {
int diffx = init[i].first - p[1].first,
diffy = init[i].second - p[1].second;
memset(prv, 0, sizeof(prv));
memset(nxt, 0, sizeof(nxt));
memset(sol, 0, sizeof(sol));
for(int j = 1; j <= N; ++j)
if(i != j && match[make_pair(p[j].first + diffx, p[j].second + diffy)]) {
int index = match[make_pair(p[j].first + diffx, p[j].second + diffy)];
nxt[j] = index;
prv[index] = j;
}
bool ok = true;
for(int j = 1; j <= N && ok; ++j) {
int curr = j;
while(prv[curr] && prv[curr] != j)
curr = prv[curr];
bool colour = false;
while(!sol[curr] && curr) {
sol[curr] = colour + 1;
colour ^= 1;
curr = nxt[curr];
}
if(colour)
ok = false;
}
if(ok) {
for(int j = 1; j <= N; ++j)
fout << sol[j] << '\n';
return 0;
}
}
}
}