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Cod sursa(job #271079)
using namespace std;
#include <set>
#include <map>
#include <list>
#include <deque>
#include <stack>
#include <queue>
#include <cmath>
#include <cstdio>
#include <vector>
#include <string>
#include <bitset>
#include <utility>
#include <algorithm>
#define pb push_back
#define sz size
#define f first
#define s second
#define II inline
#define ll long long
#define db double
#define FOR(i,a,b) for(int i=a;i<=b;++i)
#define all(v) v.begin() , v.end()
#define CC(v) memset((v),0,sizeof((v)))
#define CP(v,w) memcpy((v),(w),sizeof((w)))
#define mp make_pair
#define IN "iv.in"
#define OUT "iv.out"
#define N_MAX 1<<9
#define mod 3210121
typedef vector<int> VI;
typedef pair<int,int> pi;
typedef vector<string> VS;
int N,M;
char V1[N_MAX],V2[N_MAX];
int A[N_MAX][N_MAX][N_MAX];//,B[N_MAX][N_MAX];
II void scan()
{
freopen(IN,"r",stdin);
freopen(OUT,"w",stdout);
fgets(V1+1,1<<10,stdin);
fgets(V2+1,1<<10,stdin);
N = strlen(V1+1) - 1;
M = strlen(V2+1) - 1;
}
II void solve()
{
int rez(0);
A[0][N+1][0] = 1;
// int h1 = N>>1,h2 = h1+1,h3 = M>>1,h4 = h3+1;
FOR(i1,0,N)
for(int i2=N+1;i2>i1;--i2)
FOR(i3,0,M)
{
int i4 = (N+M - i3 + 2) - (i1+i2);
if(V1[i1+1] == V2[i3+1])
A[i1+1][i2][i3+1] += A[i1][i2][i3];
if(V1[i1+1] == V2[i4-1])
A[i1+1][i2][i3] += A[i1][i2][i3];
if(V1[i2-1] == V2[i3+1])
A[i1][i2-1][i3+1] += A[i1][i2][i3];
if(V1[i2-1] == V2[i4-1])
A[i1][i2-1][i3] += A[i1][i2][i3];
// printf("%d %d %d %d : %d\n",i1,i2,i3,i4,A[i1][i2][i3]);
if(i1+1 == i2 && i3+1 == i4)
{
rez += A[i1][i2][i3];
if(rez > mod)
rez -= mod;
}
}
printf("%d\n",rez);
}
int main()
{
scan();
solve();
return 0;
}