#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<algorithm>
#include<iostream>
#include<vector>
#include<stack>
#include<queue>
using namespace std;
#define MAXEDGE 100001
#define MAXN 40001
#define MAXM 410
struct EDGE{int to,v,next;};
struct QUESTION{int to,num,next;};
EDGE a[MAXEDGE];
QUESTION b[MAXM];
int DATA,N,M,edge[MAXN],question[MAXN],tot1=0,tot2=0,ansf[MAXM],anst[MAXM];
Int fa[MAXN],LCA[MAXM],dist[MAXN];//dist[i] records the distance from point i to the root node
bool vis[MAXN];
void add_edge(int x,int y,int value)
{
a[++tot1].to=y;//the arrival point of this side
a[tot1].v=value;//the length of this side
a[tot1].next=edge[x];//The last edge number with the same initial point as this edge
Edge[x]=tot1;//update number
}
void add_question(int x,int y,int number)
{
b[++tot2].to=y;//The point label of this query
b[tot2].num=number;//the corresponding number of this query
b[tot2].next=question[x];
question[x]=tot2;
}
int get(int x)
{
if(fa[x]==x) return x;
return fa[x]=get(fa[x]);
}
void Tarjan(int x)
{
Fa[x]=x;//As the current root node, point its father to himself
Vis[x]=true;//mark that the point has passed
for(int i=question[x];i;i=b[i].next)
{
int now_to=b[i].to;
If(vis[now_to])// If the subtrees of its child nodes and child nodes are all accessed, this step will be entered, judged by vis
LCA[b[i].num]=get(now_to);//Update LCA value
}
for(int i=edge[x];i;i=a[i].next)
{
int now_to=a[i].to;
if(!vis[now_to])
{
Dist[now_to]=dist[x]+a[i].v;//Update dist value
Tarjan (now_to); / / is equivalent to reverting now_to as the root node
Fa[now_to]=x;//update the father of the child node
}
}
}
int main()
{
freopen("input.in","r",stdin);
freopen("output.out","w",stdout);
scanf("%d",&DATA);
for(int now=1;now<=DATA;now++)
{
memset(vis,false,sizeof(vis));
memset(edge,0,sizeof(edge));
memset(question,0,sizeof(question));
memset(a,0,sizeof(a));
memset(b,0,sizeof(b));
memset(dist,0,sizeof(dist));
memset(fa,0,sizeof(fa));
tot1=0,tot2=0;
scanf("%d%d",&N,&M);
for(int i=1;i<=N;i++)
Fa[i]=i;//First point the father node of all nodes to themselves
for(int i=1;i<=N-1;i++)
{
int A,B,C;
scanf("%d%d%d",&A,&B,&C);
Add_edge(A,B,C);//Create undirected edges, store with a linked list
add_edge(B,A,C);
}
for(int i=1;i<=M;i++)
{
int A,B;
scanf("%d%d",&A,&B);
Add_question(A,B,i);//Use two records here to ensure that you can take care of these two points when updating the LCA.
add_question(B,A,i);
ansf[i]=A,anst[i]=B;
}
Tarjan(1);
for(int i=1;i<=M;i++)
printf("%d\n",dist[ansf[i]]+dist[anst[i]]-2*dist[LCA[i]]);
}
//system("pause");
return 0;
}