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#include <bits/stdc++.h>
#define maxn 100000
#define logmaxn 17
using namespace std;
class InParser {
private:
FILE *fin;
char *buff;
int sp;
char read_ch() {
++sp;
if (sp == 4096) {
sp = 0;
fread(buff, 1, 4096, fin);
}
return buff[sp];
}
public:
InParser(const char* nume) {
fin = fopen(nume, "r");
buff = new char[4096]();
sp = 4095;
}
InParser& operator >> (int &n) {
char c;
while (!isdigit(c = read_ch()) && c != '-');
int sgn = 1;
if (c == '-') {
n = 0;
sgn = -1;
} else {
n = c - '0';
}
while (isdigit(c = read_ch())) {
n = 10 * n + c - '0';
}
n *= sgn;
return *this;
}
InParser& operator >> (long long &n) {
char c;
n = 0;
while (!isdigit(c = read_ch()) && c != '-');
long long sgn = 1;
if (c == '-') {
n = 0;
sgn = -1;
} else {
n = c - '0';
}
while (isdigit(c = read_ch())) {
n = 10 * n + c - '0';
}
n *= sgn;
return *this;
}
};
class OutParser {
private:
FILE *fout;
char *buff;
int sp;
void write_ch(char ch) {
if (sp == 50000) {
fwrite(buff, 1, 50000, fout);
sp = 0;
buff[sp++] = ch;
} else {
buff[sp++] = ch;
}
}
public:
OutParser(const char* name) {
fout = fopen(name, "w");
buff = new char[50000]();
sp = 0;
}
~OutParser() {
fwrite(buff, 1, sp, fout);
fclose(fout);
}
OutParser& operator << (int vu32) {
if (vu32 <= 9) {
write_ch(vu32 + '0');
} else {
(*this) << (vu32 / 10);
write_ch(vu32 % 10 + '0');
}
return *this;
}
OutParser& operator << (long long vu64) {
if (vu64 <= 9) {
write_ch(vu64 + '0');
} else {
(*this) << (vu64 / 10);
write_ch(vu64 % 10 + '0');
}
return *this;
}
OutParser& operator << (char ch) {
write_ch(ch);
return *this;
}
OutParser& operator << (const char *ch) {
while (*ch) {
write_ch(*ch);
++ch;
}
return *this;
}
};
InParser fin ("rmq.in");
OutParser fout ("rmq.out");
int n, Q, x, y, k, v[maxn + 1], M[maxn + 1][logmaxn + 1];
int main () {
fin >> n >> Q;
for (int i = 0; i < n; i ++) {
fin >> v[i];
M[i][0] = i;
}
for (int j = 1; (1 << j) <= n; j ++)
for (int i = 0; i + (1 << j) - 1 < n; i ++)
if (v[M[i][j - 1]] < v[M[i + (1 << (j - 1))][j - 1]]) M[i][j] = M[i][j - 1];
else M[i][j] = M[i + (1 << (j - 1))][j - 1];
while (Q --) {
fin >> x >> y;
x --, y --;
k = log (y - x + 1);
if (v[M[x][k]] <= v[M[y - (1 << k) + 1][k]]) fout << v[M[x][k]] << '\n';
else fout << v[M[y - (1 << k) + 1][k]] << '\n';
}
return 0;
}