Pagini recente » Cod sursa (job #430342) | Cod sursa (job #1251913) | Cod sursa (job #674867) | Cod sursa (job #386213) | Cod sursa (job #2603031)
#include <iostream>
#include <fstream>
using namespace std;
ifstream f("fractii.in");
ofstream g("fractii.out");
int N,nrp;
bool ciur[1000001];
int p[80000];
int phi(int n)
{
int result = n; // Initialize result as n
// Consider all prime factors of n and subtract their
// multiples from result
for (int p = 2; p * p <= n; ++p) {
// Check if p is a prime factor.
if (n % p == 0) {
// If yes, then update n and result
while (n % p == 0)
n /= p;
result -= result / p;
}
}
// If n has a prime factor greater than sqrt(n)
// (There can be at-most one such prime factor)
if (n > 1)
result -= result / n;
return result;
}
int main()
{
f>>N;
int s=0;
for(int i=1;i<=N;i++)
s+=phi(i);
s=s*2-1;
g<<s;
return 0;
}