#include <fstream>
using namespace std;
ifstream cin("iepuri.in");
ofstream cout("iepuri.out");
int main()
{
    long long int t, a, b, c, v[20000], n;
    cin >> t;
    for (int i = 1; i <= t; i++)
    {
        cin >> v[1] >> v[2] >> v[3] >> a >> b >> c >> n;
        for (long long int i = 4; i <= n + 1; i++)
        {
            v[i] = a * v[i-1] + b * v[i-2] + c * v[i-3];
        }
        cout << v[n+1] % 666013 << '\n';
    }
    return 0;
}