Cod sursa(job #2409661)

Utilizator razviii237Uzum Razvan razviii237 Data 19 aprilie 2019 12:34:25
Problema Secventa Scor 100
Compilator cpp-64 Status done
Runda Arhiva de probleme Marime 2.03 kb
#include <iostream>
#include <fstream>
#include <cstdio>

using namespace std;

class InParser {
private:
	FILE *fin;
	char *buff;
	int sp;

	char read_ch() {
		++sp;
		if (sp == 4096) {
			sp = 0;
			fread(buff, 1, 4096, fin);
		}
		return buff[sp];
	}

public:
	InParser(const char* nume) {
		fin = fopen(nume, "r");
		buff = new char[4096]();
		sp = 4095;
	}

	InParser& operator >> (int &n) {
		char c;
		while (!isdigit(c = read_ch()) && c != '-');
		int sgn = 1;
		if (c == '-') {
			n = 0;
			sgn = -1;
		} else {
			n = c - '0';
		}
		while (isdigit(c = read_ch())) {
			n = 10 * n + c - '0';
		}
		n *= sgn;
		return *this;
	}

	InParser& operator >> (long long &n) {
		char c;
		n = 0;
		while (!isdigit(c = read_ch()) && c != '-');
		long long sgn = 1;
		if (c == '-') {
			n = 0;
			sgn = -1;
		} else {
			n = c - '0';
		}
		while (isdigit(c = read_ch())) {
			n = 10 * n + c - '0';
		}
		n *= sgn;
		return *this;
	}
};

InParser f("secventa.in");
ofstream g("secventa.out");

struct xy { int x, y, z; };

const int maxn = 5e5+5;

xy q[maxn]; int k, p;

int n, m, i, x;
xy best;
int v[maxn];

bool operator > (xy a, xy b) { return a.x > b.x; }

int a, b, len;

/*void bs(int x) {
    int b = 1 << 19, r = k + 1;
    while(b > 0) {
        if(r - b >= p && q[r - b].x > x) {
            r -= b;
        }
        b >>= 1;
    }
    k = r - 1;
}*/

int main()
{
    best = {-0x3f3f3f3f, 0, 0};
    f >> n >> m;
    for(i = 1; i <= n; i ++) {
        f >> x;
        v[i] = x;
        if(p == 0 || q[p].y == i - m) { ++ p; }

        while(k >= p && x < q[k].x) {
            -- k;
        }
        //bs(x);

        int val3 = q[k].y + 1;
        if(k < p) {
            val3 = i - m + 1;
            if(val3 < 1) { val3 = 1; }
        }

        q[++k] = {x, i, val3};
        if(q[p] > best && i >= m) { best = q[p]; }
    }
    g << best.z << ' ' << best.z + m - 1 << ' ' << best.x << '\n';
    //f.close();
    g.close();
    return 0;
}