#include<iostream>
#include<fstream>

using namespace std;

ifstream in("permutari.in");
ofstream out("permutari.out");

bool used[10];
int perm[10],n;

void back(int lv)
{
    if(lv>n)
    {
        for(int i=1;i<lv;i++)
            out<<perm[i];
        out<<endl;
        return;
    }
    for(int i=1;i<=n;i++)
    {
        if(!used[i])
        {
            perm[lv]=i;
            used[i]=1;
            back(lv+1);
            used[i]=0;
        }
    }

}

int main()
{
    in>>n;
    back(1);
    in.close();
    out.close();
    return 0;
}