Cod sursa(job #2375074)

Utilizator stefdascalescuStefan Dascalescu stefdascalescu Data 7 martie 2019 22:07:24
Problema Radix Sort Scor 100
Compilator cpp-64 Status done
Runda Arhiva educationala Marime 2.19 kb
#include<bits/stdc++.h>
using namespace std;
ifstream f("radixsort.in");
class OutParser {
private:
    FILE *fout;
    char *buff;
    int sp;

    void write_ch(char ch) {
        if (sp == 50000) {
            fwrite(buff, 1, 50000, fout);
            sp = 0;
            buff[sp++] = ch;
        } else {
            buff[sp++] = ch;
        }
    }


public:
    OutParser(const char* name) {
        fout = fopen(name, "w");
        buff = new char[50000]();
        sp = 0;
    }
    ~OutParser() {
        fwrite(buff, 1, sp, fout);
        fclose(fout);
    }

    OutParser& operator << (int vu32) {
        if (vu32 <= 9) {
            write_ch(vu32 + '0');
        } else {
            (*this) << (vu32 / 10);
            write_ch(vu32 % 10 + '0');
        }
        return *this;
    }

    OutParser& operator << (long long vu64) {
        if (vu64 <= 9) {
            write_ch(vu64 + '0');
        } else {
            (*this) << (vu64 / 10);
            write_ch(vu64 % 10 + '0');
        }
        return *this;
    }

    OutParser& operator << (char ch) {
        write_ch(ch);
        return *this;
    }
    OutParser& operator << (const char *ch) {
        while (*ch) {
            write_ch(*ch);
            ++ch;
        }
        return *this;
    }
}g("radixsort.out");
int n, a, b, c;
int v[10000002], v2[10000002];
int sm[260];
int main()
{
    f >> n >> a >> b >> c;
    v[1] = b;
    for(int i = 2; i <= n; ++i)
    {
        long long z = (1LL * a * v[i-1] + b) % c;
        v[i] = z;
    }
    int nrb = (1<<8) - 1;
    for(int i = 0; i <= 3; ++i)
    {
        memset(sm, 0, sizeof(sm));
        for(int j = 1; j <= n; ++j)
        {
            int xx = (v[j] & nrb);
            xx >>= (8 * i);
            sm[xx + 1]++;
        }
        for(int j = 1; j <= 255; ++j)
            sm[j] += sm[j-1];
        int pz = 0;
        for(int j = 1; j <= n; ++j)
        {
            int xx = (v[j] & nrb);
            xx >>= (8 * i);
            v2[++sm[xx]] = v[j];
        }
        memcpy(v, v2, sizeof(v2));
        nrb <<= 8;
    }
    for(int j = 1; j <= n; j += 10)
        g << v[j] << " ";
    return 0;
}